Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 12 of 14.
Abc said:
1 decade ago
Thanks muhundhan thats great.
Nikhil said:
1 decade ago
Why you write 283- (3. 2*10)?
Kalaivani said:
1 decade ago
Why you write 283- (3. 2*10)?
Arti said:
1 decade ago
Thanks muhundhan thats great.
Shravya said:
8 years ago
Why do we minus 282-(3.2*10)?
Swarna said:
9 years ago
What is the formula of this?
Leena said:
7 years ago
Nice explanation, thank you.
Vinod said:
2 decades ago
Why we are writing 3.2*10 ?
Shobhita said:
10 years ago
Why we are minus 282 - 32?
(1)
Rituparna Sengupta said:
1 decade ago
(282-(3.2*10))/40 = 6.25.
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