Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 13 of 14.
Vinod said:
2 decades ago
Why we are writing 3.2*10 ?
Shobhita said:
1 decade ago
Why we are minus 282 - 32?
(1)
Rituparna Sengupta said:
1 decade ago
(282-(3.2*10))/40 = 6.25.
Poulami said:
10 years ago
@Tanvir, you are superb.
Maha said:
1 decade ago
Thanks vignesh mahesh.
Isha panchal said:
1 decade ago
Muhundhan sir thanks.
Radhika said:
1 decade ago
Is there any formula?
Red bull said:
8 years ago
Thanks @Pratik Mehta.
Manish said:
1 decade ago
I need basic method.
(1)
Sanjay gurjar said:
10 years ago
282 - 32/40 = 6.25.
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