Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
6.25
6.5
6.75
7
Answer: Option
Explanation:

Required run rate = 282 - (3.2 x 10) = 250    = 6.25
40 40

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:
137 comments Page 8 of 14.

Bhavik said:   8 months ago
10 overs -> 3.2 RR ==> so we get 32runs in 10overs.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
(31)

Cherry aishu said:   2 years ago
Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(6)

Jitender said:   1 decade ago
Ten over run rate is 3.2

So 10*3.2= 32.

Then Target 282-32 = 250.

Remaining over is 40.

250/40= 6.25 answer.
(1)

Padmashri said:   1 decade ago
RR runs Target-282.

1-10 overs 3.2 32.

11-40 overs ? 250.

RR = Runs/Overs.

RR = 250/40.

Answer: 6.25.

Nigus said:   8 years ago
@Biswaji.

it means ; 10x3.2+40x(x)=282.
so,
32+40x=282,
40x=282-32,
40x=250,
x=250/40,
x=6.25.

Manalan said:   5 years ago
First 10 over,
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.

250 ÷ 40 = 6.25,
6.25.
(9)

Colbie said:   1 decade ago
Mr.A average on 4 test is 80. what does he need on his fifth test to raise his average to 84?

Ravi said:   1 decade ago
We need to calculate remaining average so we have to deduct score whick is already scored.

Pradeep said:   1 decade ago
Total run in 10 over=10*3.2=32
Required run in 40 over=282-32=250
Hence avg=250/40 =6.25

Manish said:   1 decade ago
Why we Divided 40 over because remaining over 30 and you also given the 10 over run ate?


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