Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 7 of 14.
Siva said:
9 years ago
@Chahat.
First, 15 overs team scored 120 runs at rate 6.2 and 183 runs need to be scored to reach 303 in 35 overs so req rate is 183/35 = 5.22.
First, 15 overs team scored 120 runs at rate 6.2 and 183 runs need to be scored to reach 303 in 35 overs so req rate is 183/35 = 5.22.
Tintu mathew said:
1 decade ago
The simple method is
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
GAUTAM said:
1 decade ago
THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
Rashmi said:
1 decade ago
Is there any short cut for this?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
Balaji said:
4 years ago
First 10 overs run rate 3.2=3.2 * 10 = 32.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
(6)
Shruti godi said:
7 years ago
First 10 overs ----> 3.2 runrate.
Remaining 40 overs ----> x runrate.
(10*3.2)+(40*x) = 282,
32+40x = 282,
X = 25/4,
X = 6.25.
Remaining 40 overs ----> x runrate.
(10*3.2)+(40*x) = 282,
32+40x = 282,
X = 25/4,
X = 6.25.
(2)
Muhundhan said:
2 decades ago
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
Bhavik said:
2 weeks ago
10 overs -> 3.2 RR ==> so we get 32runs in 10overs.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
(4)
Cherry aishu said:
1 year ago
Avg of 6 months = (6435+6927+6855+7230+6562+x)/6 = 6500.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(34009+x)/6 = 6500,
34009+x = 39000,
x = 39000-34009,
x = 4991.
(6)
Jitender said:
10 years ago
Ten over run rate is 3.2
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
(1)
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