Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 6 of 14.
Hemanth said:
1 decade ago
First 10 overs they scored 32 runs====3.2*10.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Chahat sony said:
9 years ago
In the first 15 overs of a one-day cricket match, the run rate was only 6.2 to reach the target of 303 runs in the remaining 35 overs, the run rate should be?
Please solve it.
Please solve it.
Nish said:
9 years ago
Over * run rate = run => 10 * 3.2 = 32 runs.
Target = 282, our score is 32 runs so required run => 282 - 32 = 250.
Over * run rate = runs.
So run rate = 250/40 = 6.25.
Target = 282, our score is 32 runs so required run => 282 - 32 = 250.
Over * run rate = runs.
So run rate = 250/40 = 6.25.
Pranav said:
10 years ago
Can anyone please give the solution of this.
A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th innings.
A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th innings.
Arunpandiyan said:
10 months ago
In the first 10 overs, we got a total runs is 10 * 3.2 = 32
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
(16)
Ajay Kumar said:
6 years ago
The first 10 overs run rate is 3.2 which means score will be taken 32 runs per 10 overs.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
(2)
Aymen said:
1 decade ago
Muhundan you are really very helpful.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
Amit said:
1 decade ago
Using basics of cricket.
Runs in 10 overs at the rate of 3.2 = 32.
Target 282.
Remaining runs 282-32 = 250.
Remaining overs 40.
Thus run rate 250/40 = 6.25.
Runs in 10 overs at the rate of 3.2 = 32.
Target 282.
Remaining runs 282-32 = 250.
Remaining overs 40.
Thus run rate 250/40 = 6.25.
Pratik Mehta said:
2 decades ago
@Kavita : Run rate * overs = runs scored.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
Santhosh said:
1 decade ago
First we calculate 10 overs score using run rate (3.2).
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
(1)
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