Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 6 of 14.
Pranav said:
9 years ago
Can anyone please give the solution of this.
A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th innings.
A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th innings.
Arunpandiyan said:
2 months ago
In the first 10 overs, we got a total runs is 10 * 3.2 = 32
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
(10)
Ajay Kumar said:
6 years ago
The first 10 overs run rate is 3.2 which means score will be taken 32 runs per 10 overs.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
(2)
Aymen said:
1 decade ago
Muhundan you are really very helpful.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
Amit said:
1 decade ago
Using basics of cricket.
Runs in 10 overs at the rate of 3.2 = 32.
Target 282.
Remaining runs 282-32 = 250.
Remaining overs 40.
Thus run rate 250/40 = 6.25.
Runs in 10 overs at the rate of 3.2 = 32.
Target 282.
Remaining runs 282-32 = 250.
Remaining overs 40.
Thus run rate 250/40 = 6.25.
Pratik Mehta said:
2 decades ago
@Kavita : Run rate * overs = runs scored.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
So now Run rate = Runs scored/required / overs.
There 282 - (3.2 x 10) = Runs required
Remaining overs are 40.
Santhosh said:
10 years ago
First we calculate 10 overs score using run rate (3.2).
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
(1)
Suman said:
9 years ago
Run = (no of runs took in one over)/(total possible no of runs),
So, instead of 3.2 = x/10, it should be 3.2 = x/(10 * 6),
Since, 1 over has 6 runs?
So, instead of 3.2 = x/10, it should be 3.2 = x/(10 * 6),
Since, 1 over has 6 runs?
Bhargavi said:
8 years ago
A batsman makes a score of 87runs in the 17th inning & thus increases his avg by 3. Find his avg after 17th inning? Can anyone solve this problem?
Karthi said:
10 months ago
First 10 - run rate 3.2
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
(43)
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