Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 5 of 14.
Rahul Vishwakarma said:
5 years ago
Left over = 40-10 = 30overs.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
(2)
Sathi said:
1 decade ago
@kalaivani,
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
Ashish said:
1 decade ago
Hi friends, please think logically.
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
Vinod Anand said:
1 decade ago
In the first 10 overs the run rate was = 3.2.
Than total run is = 32.
Where total target is - 282.
Let the remaining 40 overs run rate is = x.
32+40x = 282.
40x = 250.
x = 25/4 = 6.25 answer.
Than total run is = 32.
Where total target is - 282.
Let the remaining 40 overs run rate is = x.
32+40x = 282.
40x = 250.
x = 25/4 = 6.25 answer.
Amit soni said:
9 years ago
Its real solution is that,
282 = 5.64 * 50 = 40 * req run rate + 3.2 * 10 then answer is 6.25 means.
Total scored run in 50 over = total run rate * over = 40over * run rate + 10over * run rate.
282 = 5.64 * 50 = 40 * req run rate + 3.2 * 10 then answer is 6.25 means.
Total scored run in 50 over = total run rate * over = 40over * run rate + 10over * run rate.
Kondru Durga Srinu said:
1 year ago
So we calculate the runs in the first 10 overs = 10 * 3.2
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
First 10 overs they got 32 runs
Total runs for 50 overs is 282
Then, the remaining 40 overs they got = 282 - 32 = 250.
250/40 = 6.25
(11)
Sudhir Joshi said:
1 decade ago
In 10 overs run scored is 250, and in remaining 40 overs to get the total target of 282, remaining runs are 250 as 32 has been scored. Divide 250 by 40 that will be the required run-rate.
Hemanth said:
1 decade ago
First 10 overs they scored 32 runs====3.2*10.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Chahat sony said:
9 years ago
In the first 15 overs of a one-day cricket match, the run rate was only 6.2 to reach the target of 303 runs in the remaining 35 overs, the run rate should be?
Please solve it.
Please solve it.
Nish said:
9 years ago
Over * run rate = run => 10 * 3.2 = 32 runs.
Target = 282, our score is 32 runs so required run => 282 - 32 = 250.
Over * run rate = runs.
So run rate = 250/40 = 6.25.
Target = 282, our score is 32 runs so required run => 282 - 32 = 250.
Over * run rate = runs.
So run rate = 250/40 = 6.25.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers