Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 9 of 14.
Ako venuh said:
1 decade ago
We Know Run Rate = Runs/overs.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Rituparna Sengupta said:
1 decade ago
(282-(3.2*10))/40 = 6.25.
Rituparna Sengupta said:
1 decade ago
Required run-rate = (282-(3.2*10))/40 = 6.25.
Hemanth said:
1 decade ago
First 10 overs they scored 32 runs====3.2*10.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Then we required to score 250 runs to get the score of 282 in 40 overs=======(28232 = 250 in 40 overs).
Therefore: 250/40 = 6.25.
Rashmi said:
1 decade ago
Is there any short cut for this?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
If we solve this way like long method, rest of the questions will be pending. Any one suggest me?
Raj said:
1 decade ago
10*3.2 = 32.
40*? = ?
Required = 282.
40*? = ?
Required = 282.
Sudhir Joshi said:
1 decade ago
In 10 overs run scored is 250, and in remaining 40 overs to get the total target of 282, remaining runs are 250 as 32 has been scored. Divide 250 by 40 that will be the required run-rate.
Dhananjay Gahmari said:
1 decade ago
Sorry @Palani your point of view to check answer is wrong!
GAUTAM AND AYUSH you BOTH are RIGHT.
Gautam takes the sum of first two number is 11, and Ayush takes the average first two number is 11.
So both answer is correct.
GAUTAM AND AYUSH you BOTH are RIGHT.
Gautam takes the sum of first two number is 11, and Ayush takes the average first two number is 11.
So both answer is correct.
Manish said:
1 decade ago
Why we Divided 40 over because remaining over 30 and you also given the 10 over run ate?
Palani said:
1 decade ago
@Aayush - Sorry to say but your solution is wrong.
@Aymen - The solution for your problem stated.
THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8.
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8.
11+Z/3=8.
BY TRANSPOSITION,
11+Z=3*8.
11+Z=24.
Z=24-11.
Z=13.
i.e) X+Y=11.
Z=13.
HENCE THE AVG X+Y+Z/3=8.
SO, Gautam IS RIGHT YOU'RE WRONG Ayush.
@Aymen - The solution for your problem stated.
THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8.
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8.
11+Z/3=8.
BY TRANSPOSITION,
11+Z=3*8.
11+Z=24.
Z=24-11.
Z=13.
i.e) X+Y=11.
Z=13.
HENCE THE AVG X+Y+Z/3=8.
SO, Gautam IS RIGHT YOU'RE WRONG Ayush.
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