Aptitude - Average - Discussion

The total target for 50 overs is 282 out of that first 10 overs they scored at The run rate of 3.2, which means they scored 32,
For remaining 40 overs the target is 282-32=250,

For 40 overs the target is 250.

Then for 1 over it is 250/40 = 6.25.

@Gautam - Sorry to say but your solution is wrong.
@Aymen - The solution for your problem stated.

"The average of three numbers is 8, that of the first two is 11. Find the third number?please help me." is:

Let three numbers be x,y,z.
Average of first three numbers is 8.
Hence, x+y+z/3 = 8.
=> x+y+z = 24.....eq(1).

Average of first two numbers is = 11.
Hence, x+y/2 = 11.
=> x+y = 22....eq(2).

Now substitute eq(2) value in eq(1).
Thus, 22+z = 24.
=> z = 24-22 = 2.
Answer is z = 2.
:).

What is the formula for this sum?

Formula used for this type of questions?

Using basics of cricket.

Runs in 10 overs at the rate of 3.2 = 32.

Target 282.

Remaining runs 282-32 = 250.

Remaining overs 40.

Thus run rate 250/40 = 6.25.

In the first 10 overs the run rate was = 3.2.

Than total run is = 32.

Where total target is - 282.

Let the remaining 40 overs run rate is = x.

32+40x = 282.

40x = 250.

x = 25/4 = 6.25 answer.

What is the actual formula for this type of questions?

Total run in 10 over=10*3.2=32
Required run in 40 over=282-32=250
Hence avg=250/40 =6.25

Run rate in first ten overs = 3.2
Total runs made in first ten overs = 3.2*10 = 32 runs
Remaining runs to make = 282-32 =250
Overs left = 40 overs
Average run rate = 250/40 = 6.25

So, The run rate to make 250 runs in 40 overs is 6.25 RPO(runs per over)

Excellent explanation Tarun and Deepa, Thanks a lot