Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 11 of 14.
GANGARAJU T C said:
1 decade ago
First 10 overs Score = 10 overs x 3.2 Run Rate = 32 Runs.
Total targeted runs in 50 overs = 282 Runs
Required Runs to be scored in 40 overs = 250
Total 50 overs Runs(282 Runs)-First 10 overs runs Scored(32 Runs)
Required Run Rate in 40 overs = Required Runs/Remaining overs
= 250 Runs /40 overs
= 6.25
Total targeted runs in 50 overs = 282 Runs
Required Runs to be scored in 40 overs = 250
Total 50 overs Runs(282 Runs)-First 10 overs runs Scored(32 Runs)
Required Run Rate in 40 overs = Required Runs/Remaining overs
= 250 Runs /40 overs
= 6.25
(1)
Ashish said:
1 decade ago
Hi friends, please think logically.
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250
(3) In 40 overs runs are 250.
Now, Run rate is 250/40 = 6.25 //
Ravi said:
1 decade ago
We need to calculate remaining average so we have to deduct score whick is already scored.
Naresh said:
1 decade ago
Hi friends, please think logically.
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250)
(3) Now check given answers....take 6.2runrate and 40 overs(i.e 6.25*40=250). So ans is "6.25" .
(1) Run rate of 10 ovres is 3.2 (i.e 3.2*10=32runs).
(2) Total runs are 282(i.e 282-32=250)
(3) Now check given answers....take 6.2runrate and 40 overs(i.e 6.25*40=250). So ans is "6.25" .
Maha said:
1 decade ago
Thanks vignesh mahesh.
DKB said:
1 decade ago
Pratik and Muhundhan Thanks for simplifying the problem.
Jay said:
1 decade ago
Thank you very much muhundhan. Simple answer to understand.
Radhika said:
1 decade ago
Is there any formula?
Arti said:
1 decade ago
Thanks muhundhan thats great.
GAUTAM said:
1 decade ago
THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
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