Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
6.25
6.5
6.75
7
Answer: Option
Explanation:

Required run rate = 282 - (3.2 x 10) = 250    = 6.25
40 40

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:
134 comments Page 12 of 14.

Aymen said:   1 decade ago
Muhundan you are really very helpful.

How should I solve this.

The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.

Tintu mathew said:   1 decade ago
The simple method is

total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.

Nithinvino said:   1 decade ago
Thanks muhundan.

Isha panchal said:   1 decade ago
Muhundhan sir thanks.

Tanvir said:   1 decade ago
It may be like this:
Let the required run rate be x.

Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.

Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans

Nayan das said:   1 decade ago
Very good explanation vinoth m, thanks.

Sathi said:   1 decade ago
@kalaivani,

We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.

283 is total score req for 40 overs,10*3.2=32 runs scored in the first over

Kalaivani said:   1 decade ago
Why you write 283- (3. 2*10)?

Vinoth M said:   1 decade ago
Formula is, average=sum of runs in each overs(s)/number of overs(n)
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25

Gdged said:   1 decade ago
Why we are using this formula?


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