Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
Required run rate = | ![]() |
282 - (3.2 x 10) | ![]() |
= | 250 | = 6.25 |
40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 12 of 14.
Aymen said:
1 decade ago
Muhundan you are really very helpful.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
Tintu mathew said:
1 decade ago
The simple method is
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
Nithinvino said:
1 decade ago
Thanks muhundan.
Isha panchal said:
1 decade ago
Muhundhan sir thanks.
Tanvir said:
1 decade ago
It may be like this:
Let the required run rate be x.
Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.
Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans
Let the required run rate be x.
Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.
Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans
Nayan das said:
1 decade ago
Very good explanation vinoth m, thanks.
Sathi said:
1 decade ago
@kalaivani,
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
Kalaivani said:
1 decade ago
Why you write 283- (3. 2*10)?
Vinoth M said:
1 decade ago
Formula is, average=sum of runs in each overs(s)/number of overs(n)
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25
Gdged said:
1 decade ago
Why we are using this formula?
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