Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 13 of 14.
Srinivas reddy said:
1 decade ago
First we calculate the total runs done in 10 overs by using run rate ie 10*3.2 (runs per over) = 32.
Remaining runs is 283-32 = 250.
The run rate required to achieve the target is 250 (required runs to do) /40 (remaining overs).
Remaining runs is 283-32 = 250.
The run rate required to achieve the target is 250 (required runs to do) /40 (remaining overs).
Swathy said:
1 decade ago
Excellent deepa and muhunthan.
Deepa said:
1 decade ago
@nikhil
First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)
First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)
Nikhil said:
1 decade ago
Why you write 283- (3. 2*10)?
Avinsh said:
1 decade ago
How to solve given problem:.
Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.
Rajana traveled a journey of 500km with speed of 50km/hr for 5 liter and traveled withe speed of 60km/hr for 5hr and then is last 5hr covers a distance of 700km and after taking rest of 3 hr again traveled. For 2 hr by covering a distance 120km find average of speed.
Tarun said:
1 decade ago
282 are not minus,here ((3.2(current run rate)*10(overs))=32runs)
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.
are subtracted from total required runs,so 282-32=250 are the runs required in other 40 overs,
so required run rate=
250/40=6.25 runs per over.
Swetha said:
1 decade ago
Why are you minus that 282 runs?
Abc said:
1 decade ago
Thanks muhundhan thats great.
Muhundhan said:
2 decades ago
So we calculate the runs in the first 10 overs
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
first 10 overs they got 32 runs
remaining 40 overs they got 250
250 / 40 =6.25
Ranjith said:
2 decades ago
Why do we minus 282-(3.2*10)...?
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