Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
Required run rate = | ![]() |
282 - (3.2 x 10) | ![]() |
= | 250 | = 6.25 |
40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 8 of 14.
Jitender said:
10 years ago
Ten over run rate is 3.2
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
So 10*3.2= 32.
Then Target 282-32 = 250.
Remaining over is 40.
250/40= 6.25 answer.
(1)
Akila said:
10 years ago
Let the run in 5th match be x.
Total runs scored in 4 matches = 80*4 = 320.
Now, when 320 added with x avg becomes 84 (as per question).
= (320+x)/5 = 84.
x = 100.
Answer check: (320+100)/5 = 84.
Total runs scored in 4 matches = 80*4 = 320.
Now, when 320 added with x avg becomes 84 (as per question).
= (320+x)/5 = 84.
x = 100.
Answer check: (320+100)/5 = 84.
(1)
Santhosh said:
10 years ago
First we calculate 10 overs score using run rate (3.2).
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
= 10*3.2 = 32 runs.
Target = 282.
We need 250 runs in 40 overs (282-32).
So, 250/40 = 6.25.
(1)
Sameer Rolekar said:
1 decade ago
Note we have a formula => Runrate*Overs = Run Scored.
1st > we have given Runrate and overs, so we are calculating the run scored.
ie. 3.2*10 = ? (Run Scored) we get Run scored = 32.
2nd > we have to find the run scored in the remaining 40 overs so we subtract the run scored in the first 10 over from the Total score.
i.e. 282-32=250.
Now we have run scored=250 and overs=40, so we find will find the run rate.
i.e. Runrate*Overs = Run Scored.
Runrate*40 = 250.
Answer==> Runrate = 6.25.
1st > we have given Runrate and overs, so we are calculating the run scored.
ie. 3.2*10 = ? (Run Scored) we get Run scored = 32.
2nd > we have to find the run scored in the remaining 40 overs so we subtract the run scored in the first 10 over from the Total score.
i.e. 282-32=250.
Now we have run scored=250 and overs=40, so we find will find the run rate.
i.e. Runrate*Overs = Run Scored.
Runrate*40 = 250.
Answer==> Runrate = 6.25.
(1)
Swetha said:
1 decade ago
Iron manufacturing company produced a total of 3000 tons of iron in January of a particular year. Starting from February its production increased by 200 tons every month over the previous months until the end of that year. Find its average monthly production (in tons) for that year.
(2)
Padmashri said:
1 decade ago
RR runs Target-282.
1-10 overs 3.2 32.
11-40 overs ? 250.
RR = Runs/Overs.
RR = 250/40.
Answer: 6.25.
1-10 overs 3.2 32.
11-40 overs ? 250.
RR = Runs/Overs.
RR = 250/40.
Answer: 6.25.
Vasavi said:
1 decade ago
@Apple.
You give example test match in that problem 80*4 = 320 but you tack it as 360?
You give example test match in that problem 80*4 = 320 but you tack it as 360?
Ako venuh said:
1 decade ago
We Know Run Rate = Runs/overs.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Therefore, in the first 10 overs.
Run Rate = Runs/Overs.
3.2 = Runs/10.
Runs = 3.2*10.
Runs = 32.
Now 32 runs is scored in the first 10 Overs.
Target = 282.
Target = 282-32 = 250.
Run Rate = Target runs/Remaining Overs.
Run Rate = 250/40.
Run Rate = 6.25.
Rituparna Sengupta said:
1 decade ago
(282-(3.2*10))/40 = 6.25.
Rituparna Sengupta said:
1 decade ago
Required run-rate = (282-(3.2*10))/40 = 6.25.
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