Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 46)
46.
The total number of digits used in numbering the pages of a book having 366 pages is
Answer: Option
Explanation:
Total number of digits
= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.
Discussion:
22 comments Page 2 of 3.
Shweta said:
10 years ago
Sum of digits of a book is 3186. Find the total pages of book?
Hashi said:
9 years ago
Thanks a lot @Chandan Nayak & @Varinder.
Chetan said:
9 years ago
I do not understand clearly. Please explain it.
Krishna said:
8 years ago
I don't understand this. Please help me to get it.
Rishav said:
8 years ago
Not understanding. Please help me.
Pranav said:
8 years ago
I didn't understand this problem clearly please explain me.
Harvindra said:
7 years ago
Thanks for explaining the answer.
(1)
Sadam said:
7 years ago
@Shweta.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Muhammad umair zaman said:
6 years ago
No @Sadam.
Book has only 366 pages.
Book has only 366 pages.
Sunita tamang said:
6 years ago
how is 1000 -1075
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