# Verbal Reasoning - Arithmetic Reasoning

#### Why should I learn to solve Verbal Reasoning questions and answers section on "Arithmetic Reasoning"?

Learn and practise solving Verbal Reasoning questions and answers section on "Arithmetic Reasoning" to enhance your skills so that you can clear interviews, competitive examinations, and various entrance tests (CAT, GATE, GRE, MAT, bank exams, railway exams, etc.) with full confidence.

#### Where can I get the Verbal Reasoning questions and answers section on "Arithmetic Reasoning"?

IndiaBIX provides you with numerous Verbal Reasoning questions and answers based on "Arithmetic Reasoning" along with fully solved examples and detailed explanations that will be easy to understand.

#### Where can I get the Verbal Reasoning section on "Arithmetic Reasoning" MCQ-type interview questions and answers (objective type, multiple choice)?

Here you can find multiple-choice Verbal Reasoning questions and answers based on "Arithmetic Reasoning" for your placement interviews and competitive exams. Objective-type and true-or-false-type questions are given too.

#### How do I download the Verbal Reasoning questions and answers section on "Arithmetic Reasoning" in PDF format?

You can download the Verbal Reasoning quiz questions and answers section on "Arithmetic Reasoning" as PDF files or eBooks.

#### How do I solve Verbal Reasoning quiz problems based on "Arithmetic Reasoning"?

You can easily solve Verbal Reasoning quiz problems based on "Arithmetic Reasoning" by practising the given exercises, including shortcuts and tricks.

- Arithmetic Reasoning - Section 1
- Arithmetic Reasoning - Section 2

Required sum = (80 - 3 x 3) years = (80 - 9) years = 71 years.

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

Clearly, we have :

B-3 = E ...(i)

B + 3 = D ...(ii)

A+B = D + E+10 ...(iii)

B = C + 2 ...(iv)

A+B + C + D + E= 133 ...(v)

From (i) and (ii), we have : 2 B = D + E ...(vi)

From (iii) and (vi), we have : A = B + 10 ...(vii)

Using (iv), (vi) and (vii) in (v), we get:

(B + 10) + B + (B - 2) + 2B = 133 5B = 125 B = 25.