Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.46)

46. 

The total number of digits used in numbering the pages of a book having 366 pages is

[A]. 732
[B]. 990
[C]. 1098
[D]. 1305

Answer: Option B

Explanation:

Total number of digits

= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)

= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.


Jyotsna Singh said: (Jun 7, 2011)  
Can anybody explain this?

Praveen said: (Aug 8, 2011)  
It says, First 9 pages having 1 digit nos (1x9).

Next 90 pages having 2 digit nos (2x90).

Remaining 267 pages having 366 nos (267x3).

Shefali Chhabra said: (Aug 31, 2012)  
I am still not clear about the solution. Where did 267 come from?

Nandhini said: (Sep 24, 2012)  
Subtracting 99 pages from 367 we get 267 including 100 page (bcoz from 100th page 3digit nos starts. ).

Chandan Nayak said: (Apr 4, 2013)  
In total there are 366 pages! out of which First 9 pages having 1 digit nos (1x9=9 digits).

Next 90 pages having 2 digit nos (2 x 90=180 digits).

Remaining 267 pages having 3 digit nos (267x3 = 801 digits) so total will be 9+180+801 = 990 digits.

Samuelgbeneka said: (Aug 3, 2013)  
From the question how did you know that the first digit has 9 pages? and that the next has 2 * 90. Please someone explain.

Varinder said: (May 14, 2014)  
1-9 is only one digit so we take 9.

10-99 is only two digits so we take 90.

Total pages 366-90-9 = 267.

Soumya said: (Aug 24, 2014)  
Why not 10? only 10 number of digits used worldwide. So number of digits used=10.

Kumar said: (Dec 7, 2014)  
Well said by Praveen am easy to understood.

Jerry said: (Nov 25, 2015)  
If you are calling it Digit, it should be 10 digits. You shouldn't have used digits.

We have ten digit used and all of them are used before reaching 366. The ten digit are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,.... I understand your solving very well. You shouldn't have used digits in your question.

Shweta said: (Feb 8, 2016)  
Sum of digits of a book is 3186. Find the total pages of book?

Hashi said: (Aug 30, 2016)  
Thanks a lot @Chandan Nayak & @Varinder.

Chetan said: (Dec 31, 2016)  
I do not understand clearly. Please explain it.

Krishna said: (Mar 6, 2017)  
I don't understand this. Please help me to get it.

Rishav said: (May 29, 2017)  
Not understanding. Please help me.

Pranav said: (Oct 21, 2017)  
I didn't understand this problem clearly please explain me.

Harvindra said: (Apr 7, 2018)  
Thanks for explaining the answer.

Sadam said: (May 24, 2018)  
@Shweta.

Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.

So, total pages for 3186 digits are 1075 Pages.

Muhammad Umair Zaman said: (Apr 6, 2019)  
No @Sadam.

Book has only 366 pages.

Sunita Tamang said: (Dec 5, 2019)  
how is 1000 -1075

Sano Vai said: (Feb 25, 2020)  
Simply: 189+ (366-99) *3= 990.

Anomie said: (Mar 28, 2020)  
There were 3 columns of digits.

1st column = 366.
2nd column = 366-9 = 357 (i.e 2nd column numbers start from end of number 9).
3rd column = 366-99 = 267 (i.e 3rd column numbers Start from end of number 99).

Hence answer will be 366+357+267= 990.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.