Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 46)
46.
The total number of digits used in numbering the pages of a book having 366 pages is
Answer: Option
Explanation:
Total number of digits
= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.
Discussion:
22 comments Page 1 of 3.
Anomie said:
6 years ago
There were 3 columns of digits.
1st column = 366.
2nd column = 366-9 = 357 (i.e 2nd column numbers start from end of number 9).
3rd column = 366-99 = 267 (i.e 3rd column numbers Start from end of number 99).
Hence answer will be 366+357+267= 990.
1st column = 366.
2nd column = 366-9 = 357 (i.e 2nd column numbers start from end of number 9).
3rd column = 366-99 = 267 (i.e 3rd column numbers Start from end of number 99).
Hence answer will be 366+357+267= 990.
(8)
Chandan Nayak said:
1 decade ago
In total there are 366 pages! out of which First 9 pages having 1 digit nos (1x9=9 digits).
Next 90 pages having 2 digit nos (2 x 90=180 digits).
Remaining 267 pages having 3 digit nos (267x3 = 801 digits) so total will be 9+180+801 = 990 digits.
Next 90 pages having 2 digit nos (2 x 90=180 digits).
Remaining 267 pages having 3 digit nos (267x3 = 801 digits) so total will be 9+180+801 = 990 digits.
(1)
Harvindra said:
8 years ago
Thanks for explaining the answer.
(1)
Hashi said:
9 years ago
Thanks a lot @Chandan Nayak & @Varinder.
Sano Vai said:
6 years ago
Simply: 189+ (366-99) *3= 990.
Sunita tamang said:
6 years ago
how is 1000 -1075
Muhammad umair zaman said:
7 years ago
No @Sadam.
Book has only 366 pages.
Book has only 366 pages.
Sadam said:
7 years ago
@Shweta.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Pranav said:
8 years ago
I didn't understand this problem clearly please explain me.
Rishav said:
8 years ago
Not understanding. Please help me.
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