Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 46)
46.
The total number of digits used in numbering the pages of a book having 366 pages is
Answer: Option
Explanation:
Total number of digits
= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 x 9 + 2 x 90 + 3 x 267) = (9 + 180 + 801) = 990.
Discussion:
22 comments Page 1 of 3.
Jerry said:
10 years ago
If you are calling it Digit, it should be 10 digits. You shouldn't have used digits.
We have ten digit used and all of them are used before reaching 366. The ten digit are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,.... I understand your solving very well. You shouldn't have used digits in your question.
We have ten digit used and all of them are used before reaching 366. The ten digit are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,.... I understand your solving very well. You shouldn't have used digits in your question.
Sadam said:
7 years ago
@Shweta.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Solution:
1-9 Pages = 9 Digits.
10-99 Pages = 90*2 = 180 Digits.
100-999 Pages = 899 * 3 = 2697 Pages.
1000-1075 Pages = 75 * 4 = 300 Digits.
Hence for 1075 Pages total digits are (9 + 180 + 2697 + 300) = 3186.
So, total pages for 3186 digits are 1075 Pages.
Anomie said:
6 years ago
There were 3 columns of digits.
1st column = 366.
2nd column = 366-9 = 357 (i.e 2nd column numbers start from end of number 9).
3rd column = 366-99 = 267 (i.e 3rd column numbers Start from end of number 99).
Hence answer will be 366+357+267= 990.
1st column = 366.
2nd column = 366-9 = 357 (i.e 2nd column numbers start from end of number 9).
3rd column = 366-99 = 267 (i.e 3rd column numbers Start from end of number 99).
Hence answer will be 366+357+267= 990.
(8)
Chandan Nayak said:
1 decade ago
In total there are 366 pages! out of which First 9 pages having 1 digit nos (1x9=9 digits).
Next 90 pages having 2 digit nos (2 x 90=180 digits).
Remaining 267 pages having 3 digit nos (267x3 = 801 digits) so total will be 9+180+801 = 990 digits.
Next 90 pages having 2 digit nos (2 x 90=180 digits).
Remaining 267 pages having 3 digit nos (267x3 = 801 digits) so total will be 9+180+801 = 990 digits.
(1)
Praveen said:
1 decade ago
It says, First 9 pages having 1 digit nos (1x9).
Next 90 pages having 2 digit nos (2x90).
Remaining 267 pages having 366 nos (267x3).
Next 90 pages having 2 digit nos (2x90).
Remaining 267 pages having 366 nos (267x3).
Samuelgbeneka said:
1 decade ago
From the question how did you know that the first digit has 9 pages? and that the next has 2 * 90. Please someone explain.
Varinder said:
1 decade ago
1-9 is only one digit so we take 9.
10-99 is only two digits so we take 90.
Total pages 366-90-9 = 267.
10-99 is only two digits so we take 90.
Total pages 366-90-9 = 267.
Nandhini said:
1 decade ago
Subtracting 99 pages from 367 we get 267 including 100 page (bcoz from 100th page 3digit nos starts. ).
Soumya said:
1 decade ago
Why not 10? only 10 number of digits used worldwide. So number of digits used=10.
Shefali chhabra said:
1 decade ago
I am still not clear about the solution. Where did 267 come from?
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