Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
52 comments Page 3 of 6.
Ankit said:
10 years ago
a^m * b^n = a*b^m+n.
(6*5)*10^5+3 = 30*10^8.
(6*5)*10^5+3 = 30*10^8.
Vinotha said:
10 years ago
Thank you all for the explanation.
Anil kumar said:
9 years ago
It's easy to understand. Thank you @Ashik.
Edward suvo said:
9 years ago
Thanks to all for giving a clear explanation.
Sohel Shaikh said:
6 years ago
Multiply the number and power is added in this question.
Kavya said:
6 days ago
(6*10^3) (5*10^5) just multiply the 6 and 5 answer is 30.
And then add the power of 10, which it means 10^ (3+5) then we get 10^8 30*10^8.
And then add the power of 10, which it means 10^ (3+5) then we get 10^8 30*10^8.
Nandu said:
1 decade ago
When we are multiplying of these numbers the powers of those numbers are added.
Ashik said:
2 decades ago
(a^m)*(a^n)=a^(m+n)
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
Rameshbabu said:
2 decades ago
Thank you for easy understandable explanation.
Murali said:
2 decades ago
Simply, the numbers 6 and 5 normal multiplication (6*5=30).
In power the numbers has been added (3+5=8).
In power the numbers has been added (3+5=8).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers