Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
50 comments Page 5 of 5.
Siva(chotu) said:
1 decade ago
This is very small problem you have known the powers addition.
That is.
You first multiply the both 6&5 then added the powers.
Therefore.
(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.
Then you get the answer.
That is.
You first multiply the both 6&5 then added the powers.
Therefore.
(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.
Then you get the answer.
Sumit kumar said:
1 decade ago
Add the power and then multiply the base term.
Guna said:
1 decade ago
Simple. In multiplication base increses.
MOHAMED SUBHAN said:
1 decade ago
6*5=30.
According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.
According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.
Amala Joseph said:
1 decade ago
Given:
(6x10^3).
(5x10^5).
{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].
6*5=30.
Therefore Answer is 30*10^8.
So answer is Option B.
(6x10^3).
(5x10^5).
{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].
6*5=30.
Therefore Answer is 30*10^8.
So answer is Option B.
Rajashree kamble said:
1 decade ago
(6*10^3) (5*0^5).
6*5 = 30 and power 3+5 = 8.
30*10^8.
6*5 = 30 and power 3+5 = 8.
30*10^8.
Lallan.k.puskar said:
1 decade ago
(6*10^3)*(5*10^5) = 6*5*10^3+5 = 30*10^8 Simple formula of use (a^n)*(a^m) = a^n+m.
Aashish jayshwal said:
1 decade ago
a^m*a^n = a^m+n.
6*5 = 30 normally multiple 10^5*10^3 = 10^8.
6*5 = 30 normally multiple 10^5*10^3 = 10^8.
Sanghamitra Samal said:
1 decade ago
(6*10^3)*(5*10^5).
10^3*10^5 = 10^8.
6*5 = 30.
10^3*10^5 = 10^8.
6*5 = 30.
Anand kumar said:
1 decade ago
{a*10^m}*{b*10^n}.
a and b multiply each other.
The power of 10 sum of each other.
{a*b}*10^(m+n).
{6*5}*10^(3+5).
30*10^8.
a and b multiply each other.
The power of 10 sum of each other.
{a*b}*10^(m+n).
{6*5}*10^(3+5).
30*10^8.
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