# Electrical Engineering - Quantities and Units - Discussion

Discussion Forum : Quantities and Units - General Questions (Q.No. 1)

1.

When these numbers are multiplied, (6 × 10

^{3}) (5 × 10^{5}), the result isDiscussion:

49 comments Page 1 of 5.
Siva(chotu) said:
1 decade ago

This is very small problem you have known the powers addition.

That is.

You first multiply the both 6&5 then added the powers.

Therefore.

(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.

Then you get the answer.

That is.

You first multiply the both 6&5 then added the powers.

Therefore.

(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.

Then you get the answer.

Raji said:
9 years ago

Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication.

= 6*10^3*5*10^5 = 30*10^8.

= 6*10^3*5*10^5 = 30*10^8.

Amala Joseph said:
1 decade ago

Given:

(6x10^3).

(5x10^5).

{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].

6*5=30.

Therefore Answer is 30*10^8.

So answer is Option B.

(6x10^3).

(5x10^5).

{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].

6*5=30.

Therefore Answer is 30*10^8.

So answer is Option B.

Ashik said:
1 decade ago

(a^m)*(a^n)=a^(m+n)

[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]

Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)

=30*10^8

[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]

Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)

=30*10^8

Ezman Ezra said:
1 decade ago

6*10^3=6000 and 5*10^5=500000

When you multiply the answers you have 3000000000, there4 this can be written as

3*10^9 or 30*10^8

When you multiply the answers you have 3000000000, there4 this can be written as

3*10^9 or 30*10^8

Kunal said:
1 decade ago

In mathematical problem, the numbers are multiplied & powers are added.

Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

Anand kumar said:
1 decade ago

{a*10^m}*{b*10^n}.

a and b multiply each other.

The power of 10 sum of each other.

{a*b}*10^(m+n).

{6*5}*10^(3+5).

30*10^8.

a and b multiply each other.

The power of 10 sum of each other.

{a*b}*10^(m+n).

{6*5}*10^(3+5).

30*10^8.

Tharanya said:
1 decade ago

(6*5)*(10^(5+3))=30*10^8

In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

Kapil Dixit said:
1 decade ago

Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.

Amarnaath said:
8 years ago

(6 * 10^3)*(5 * 10^5).

Values : 6*5 = 30(multiplication).

Powers : 5 + 3 = 8(adding).

Then the answer is (30 * 10^8).

Values : 6*5 = 30(multiplication).

Powers : 5 + 3 = 8(adding).

Then the answer is (30 * 10^8).

(2)

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