Electrical Engineering - Quantities and Units - Discussion

Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
3 × 108
30 × 108
300 × 109
3,000 × 107
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
49 comments Page 1 of 5.

Siva(chotu) said:   1 decade ago
This is very small problem you have known the powers addition.
That is.
You first multiply the both 6&5 then added the powers.
Therefore.
(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.
Then you get the answer.

Raji said:   9 years ago
Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication.

= 6*10^3*5*10^5 = 30*10^8.

Amala Joseph said:   1 decade ago
Given:
(6x10^3).
(5x10^5).

{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].

6*5=30.

Therefore Answer is 30*10^8.

So answer is Option B.

Ashik said:   1 decade ago
(a^m)*(a^n)=a^(m+n)
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]

Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8

Ezman Ezra said:   1 decade ago
6*10^3=6000 and 5*10^5=500000

When you multiply the answers you have 3000000000, there4 this can be written as

3*10^9 or 30*10^8

Kunal said:   1 decade ago
In mathematical problem, the numbers are multiplied & powers are added.

Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

Anand kumar said:   1 decade ago
{a*10^m}*{b*10^n}.
a and b multiply each other.

The power of 10 sum of each other.
{a*b}*10^(m+n).
{6*5}*10^(3+5).
30*10^8.

Tharanya said:   1 decade ago
(6*5)*(10^(5+3))=30*10^8

In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

Kapil Dixit said:   1 decade ago
Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.

Amarnaath said:   8 years ago
(6 * 10^3)*(5 * 10^5).

Values : 6*5 = 30(multiplication).
Powers : 5 + 3 = 8(adding).

Then the answer is (30 * 10^8).
(2)


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