# Electrical Engineering - Quantities and Units - Discussion

### Discussion :: Quantities and Units - General Questions (Q.No.1)

1.

When these numbers are multiplied, (6 × 103) (5 × 105), the result is

 [A]. 3 × 108 [B]. 30 × 108 [C]. 300 × 109 [D]. 3,000 × 107

Explanation:

No answer description available for this question.

 Mahalakshmi said: (Dec 10, 2010) Powers are added during multiplication so 6*5=30. 10^3+5=10^8 therefore 30*10^8.

 Ashik said: (Dec 14, 2010) (a^m)*(a^n)=a^(m+n) [p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)] Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5) =30*10^8

 Rameshbabu said: (Jan 5, 2011) Thank you for easy understandable explanation.

 Murali said: (Jan 8, 2011) Simply, the numbers 6 and 5 normal multiplication (6*5=30). In power the numbers has been added (3+5=8).

 Kitty said: (Jan 10, 2011) If the numbers are mulitiplied the exponents are added. Thanks for discussion.

 Kunal said: (Jan 29, 2011) In mathematical problem, the numbers are multiplied & powers are added. Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

 Ezman Ezra said: (Feb 15, 2011) 6*10^3=6000 and 5*10^5=500000 When you multiply the answers you have 3000000000, there4 this can be written as 3*10^9 or 30*10^8

 Tharanya said: (Mar 8, 2011) (6*5)*(10^(5+3))=30*10^8 In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

 Kapil Dixit said: (Aug 14, 2011) Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.

 Sailu said: (Sep 10, 2011) It's very easy anser.in multiply 6*5. If both bases r equal then powers must be added So (6*5)*(10^3+10^5)=30*10^8

 Santosh said: (Oct 30, 2011) I agree with ashik solution. Thank you ashik.

 Debashis said: (Nov 2, 2011) Its very easy that-6*5=30; In exponent 10^(5+3)=10^8 So the ans is 30*10^8

 Ganesh said: (Nov 3, 2011) (6 x 10^3)=6000 (5 x 10^5)=500000 6000 x 500000 = 3000000000 3000000000 = 30x10^8

 Nandu said: (Nov 29, 2011) When we are multiplying of these numbers the powers of those numbers are added.

 Pavi said: (Jan 27, 2012) (6x10^3)(5x10^5) (6x5x10^3+5) (30x10^8) So ans is Option B

 Siva(Chotu) said: (Jun 7, 2012) This is very small problem you have known the powers addition. That is. You first multiply the both 6&5 then added the powers. Therefore. (6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8. Then you get the answer.

 Sumit Kumar said: (Aug 18, 2012) Add the power and then multiply the base term.

 Guna said: (Sep 8, 2012) Simple. In multiplication base increses.

 Mohamed Subhan said: (May 25, 2013) 6*5=30. According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.

 Amala Joseph said: (Sep 9, 2013) Given: (6x10^3). (5x10^5). {(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m]. 6*5=30. Therefore Answer is 30*10^8. So answer is Option B.

 Rajashree Kamble said: (Jan 9, 2014) (6*10^3) (5*0^5). 6*5 = 30 and power 3+5 = 8. 30*10^8.

 Lallan.K.Puskar said: (Jan 22, 2014) (6*10^3)*(5*10^5) = 6*5*10^3+5 = 30*10^8 Simple formula of use (a^n)*(a^m) = a^n+m.

 Aashish Jayshwal said: (Apr 17, 2014) a^m*a^n = a^m+n. 6*5 = 30 normally multiple 10^5*10^3 = 10^8.

 Sanghamitra Samal said: (Apr 25, 2014) (6*10^3)*(5*10^5). 10^3*10^5 = 10^8. 6*5 = 30.

 Anand Kumar said: (Jun 2, 2014) {a*10^m}*{b*10^n}. a and b multiply each other. The power of 10 sum of each other. {a*b}*10^(m+n). {6*5}*10^(3+5). 30*10^8.

 Khaja said: (Jul 25, 2014) 6*5 = 30. 10^3*10^5 = 10^(3+5) = 10^8. 30*10^8.

 Santhosh Kumar said: (Jun 16, 2015) The power dissipated by a resistor of 10 ohm when a current of 2A passes through it is.

 Shailu said: (Aug 8, 2015) Is correct answer?

 Shailu said: (Aug 8, 2015) 6*5 = 30. 10 is common for both the values, Powers are added. 10^3+5 = 10^8. Total value = 30*10^8.

 Raji said: (Aug 30, 2015) Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication. = 6*10^3*5*10^5 = 30*10^8.

 Ela said: (Oct 22, 2015) 6*5 = 30. 10^3*10^5 = 10^(3+5) = 10^8. 30*10^8.

 Rajaneeesh said: (Jan 24, 2016) 6*5 = 30. 5+3 = 8. = 30*10^8.

 Ankit said: (Feb 17, 2016) a^m * b^n = a*b^m+n. (6*5)*10^5+3 = 30*10^8.

 Harshitha said: (Mar 23, 2016) (6*10^3)*(5*10^5) = 6*5*(10^3+5). = 30*10^8.

 Amarnaath said: (Apr 21, 2016) (6 * 10^3)*(5 * 10^5). Values : 6*5 = 30(multiplication). Powers : 5 + 3 = 8(adding). Then the answer is (30 * 10^8).

 Vinotha said: (Jun 8, 2016) Thank you all for the explanation.

 Anil Kumar said: (Aug 5, 2016) It's easy to understand. Thank you @Ashik.

 Edward Suvo said: (Aug 21, 2016) Thanks to all for giving a clear explanation.

 Suresh K said: (Oct 31, 2016) Thank you for explaining the answer and providing the good shortcut method.

 Dhivya said: (Jan 30, 2017) Simply the number 5 & 6 are multiplied & the powers are added.

 Jac said: (Dec 3, 2017) Values=6*5=30, Power=3+5=8.

 Lalan Kr Yadav said: (Feb 14, 2019) (6*10^3) * (5*10^5). 6*5*(10^3*10^5), 30*10^3+5, 30*10^8, Or 3*10^9. Then the answer is 30*10^8.

 Engineer Majid said: (Aug 9, 2019) The power of number is add when multiplied so that's why.

 Sohel Shaikh said: (Oct 22, 2019) Multiply the number and power is added in this question.

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