Electrical Engineering - Quantities and Units - Discussion

Discussion :: Quantities and Units - General Questions (Q.No.1)

1. 

When these numbers are multiplied, (6 × 103) (5 × 105), the result is

[A]. 3 × 108
[B]. 30 × 108
[C]. 300 × 109
[D]. 3,000 × 107

Answer: Option B

Explanation:

No answer description available for this question.

Mahalakshmi said: (Dec 10, 2010)  
Powers are added during multiplication so 6*5=30.

10^3+5=10^8 therefore 30*10^8.

Ashik said: (Dec 14, 2010)  
(a^m)*(a^n)=a^(m+n)
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]

Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8

Rameshbabu said: (Jan 5, 2011)  
Thank you for easy understandable explanation.

Murali said: (Jan 8, 2011)  
Simply, the numbers 6 and 5 normal multiplication (6*5=30).

In power the numbers has been added (3+5=8).

Kitty said: (Jan 10, 2011)  
If the numbers are mulitiplied the exponents are added.

Thanks for discussion.

Kunal said: (Jan 29, 2011)  
In mathematical problem, the numbers are multiplied & powers are added.

Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

Ezman Ezra said: (Feb 15, 2011)  
6*10^3=6000 and 5*10^5=500000

When you multiply the answers you have 3000000000, there4 this can be written as

3*10^9 or 30*10^8

Tharanya said: (Mar 8, 2011)  
(6*5)*(10^(5+3))=30*10^8

In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

Kapil Dixit said: (Aug 14, 2011)  
Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.

Sailu said: (Sep 10, 2011)  
It's very easy anser.in multiply 6*5. If both bases r equal then powers must be added

So (6*5)*(10^3+10^5)=30*10^8

Santosh said: (Oct 30, 2011)  
I agree with ashik solution. Thank you ashik.

Debashis said: (Nov 2, 2011)  
Its very easy that-6*5=30;

In exponent 10^(5+3)=10^8

So the ans is 30*10^8

Ganesh said: (Nov 3, 2011)  
(6 x 10^3)=6000
(5 x 10^5)=500000
6000 x 500000 = 3000000000
3000000000 = 30x10^8

Nandu said: (Nov 29, 2011)  
When we are multiplying of these numbers the powers of those numbers are added.

Pavi said: (Jan 27, 2012)  
(6x10^3)(5x10^5)
(6x5x10^3+5)
(30x10^8)
So ans is Option B

Siva(Chotu) said: (Jun 7, 2012)  
This is very small problem you have known the powers addition.
That is.
You first multiply the both 6&5 then added the powers.
Therefore.
(6*10^3) (5*10^5) = (6*5) (10^3+5) =30*10^8.
Then you get the answer.

Sumit Kumar said: (Aug 18, 2012)  
Add the power and then multiply the base term.

Guna said: (Sep 8, 2012)  
Simple. In multiplication base increses.

Mohamed Subhan said: (May 25, 2013)  
6*5=30.

According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.

Amala Joseph said: (Sep 9, 2013)  
Given:
(6x10^3).
(5x10^5).

{(10^3)*(10^5)} = 10^3+5 = 10^8 => [(a^n)*(a^m)=a^n+m].

6*5=30.

Therefore Answer is 30*10^8.

So answer is Option B.

Rajashree Kamble said: (Jan 9, 2014)  
(6*10^3) (5*0^5).

6*5 = 30 and power 3+5 = 8.

30*10^8.

Lallan.K.Puskar said: (Jan 22, 2014)  
(6*10^3)*(5*10^5) = 6*5*10^3+5 = 30*10^8 Simple formula of use (a^n)*(a^m) = a^n+m.

Aashish Jayshwal said: (Apr 17, 2014)  
a^m*a^n = a^m+n.

6*5 = 30 normally multiple 10^5*10^3 = 10^8.

Sanghamitra Samal said: (Apr 25, 2014)  
(6*10^3)*(5*10^5).

10^3*10^5 = 10^8.

6*5 = 30.

Anand Kumar said: (Jun 2, 2014)  
{a*10^m}*{b*10^n}.
a and b multiply each other.

The power of 10 sum of each other.
{a*b}*10^(m+n).
{6*5}*10^(3+5).
30*10^8.

Khaja said: (Jul 25, 2014)  
6*5 = 30.

10^3*10^5 = 10^(3+5) = 10^8.

30*10^8.

Santhosh Kumar said: (Jun 16, 2015)  
The power dissipated by a resistor of 10 ohm when a current of 2A passes through it is.

Shailu said: (Aug 8, 2015)  
Is correct answer?

Shailu said: (Aug 8, 2015)  
6*5 = 30.

10 is common for both the values,

Powers are added.

10^3+5 = 10^8.

Total value = 30*10^8.

Raji said: (Aug 30, 2015)  
Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication.

= 6*10^3*5*10^5 = 30*10^8.

Ela said: (Oct 22, 2015)  
6*5 = 30.

10^3*10^5 = 10^(3+5) = 10^8.

30*10^8.

Rajaneeesh said: (Jan 24, 2016)  
6*5 = 30.

5+3 = 8.

= 30*10^8.

Ankit said: (Feb 17, 2016)  
a^m * b^n = a*b^m+n.

(6*5)*10^5+3 = 30*10^8.

Harshitha said: (Mar 23, 2016)  
(6*10^3)*(5*10^5)
= 6*5*(10^3+5).
= 30*10^8.

Amarnaath said: (Apr 21, 2016)  
(6 * 10^3)*(5 * 10^5).

Values : 6*5 = 30(multiplication).
Powers : 5 + 3 = 8(adding).

Then the answer is (30 * 10^8).

Vinotha said: (Jun 8, 2016)  
Thank you all for the explanation.

Anil Kumar said: (Aug 5, 2016)  
It's easy to understand. Thank you @Ashik.

Edward Suvo said: (Aug 21, 2016)  
Thanks to all for giving a clear explanation.

Suresh K said: (Oct 31, 2016)  
Thank you for explaining the answer and providing the good shortcut method.

Dhivya said: (Jan 30, 2017)  
Simply the number 5 & 6 are multiplied & the powers are added.

Jac said: (Dec 3, 2017)  
Values=6*5=30,
Power=3+5=8.

Lalan Kr Yadav said: (Feb 14, 2019)  
(6*10^3) * (5*10^5).
6*5*(10^3*10^5),
30*10^3+5,
30*10^8,
Or 3*10^9.
Then the answer is 30*10^8.

Engineer Majid said: (Aug 9, 2019)  
The power of number is add when multiplied so that's why.

Sohel Shaikh said: (Oct 22, 2019)  
Multiply the number and power is added in this question.

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