Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
49 comments Page 1 of 5.
Mahalakshmi said:
1 decade ago
Powers are added during multiplication so 6*5=30.
10^3+5=10^8 therefore 30*10^8.
10^3+5=10^8 therefore 30*10^8.
Ashik said:
1 decade ago
(a^m)*(a^n)=a^(m+n)
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
Rameshbabu said:
1 decade ago
Thank you for easy understandable explanation.
Murali said:
1 decade ago
Simply, the numbers 6 and 5 normal multiplication (6*5=30).
In power the numbers has been added (3+5=8).
In power the numbers has been added (3+5=8).
Kitty said:
1 decade ago
If the numbers are mulitiplied the exponents are added.
Thanks for discussion.
Thanks for discussion.
Kunal said:
1 decade ago
In mathematical problem, the numbers are multiplied & powers are added.
Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.
Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.
Ezman Ezra said:
1 decade ago
6*10^3=6000 and 5*10^5=500000
When you multiply the answers you have 3000000000, there4 this can be written as
3*10^9 or 30*10^8
When you multiply the answers you have 3000000000, there4 this can be written as
3*10^9 or 30*10^8
Tharanya said:
1 decade ago
(6*5)*(10^(5+3))=30*10^8
In mathematical problem, the numbers are multiplied, power are added and finally multiply both.
In mathematical problem, the numbers are multiplied, power are added and finally multiply both.
Kapil Dixit said:
1 decade ago
Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.
Sailu said:
1 decade ago
It's very easy anser.in multiply 6*5. If both bases r equal then powers must be added
So (6*5)*(10^3+10^5)=30*10^8
So (6*5)*(10^3+10^5)=30*10^8
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