# Electrical Engineering - Quantities and Units - Discussion

Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
3 × 108
30 × 108
300 × 109
3,000 × 107
Explanation:
No answer description is available. Let's discuss.
Discussion:
49 comments Page 2 of 5.

Suresh k said:   8 years ago
Thank you for explaining the answer and providing the good shortcut method.
(1)

Edward suvo said:   8 years ago
Thanks to all for giving a clear explanation.

Anil kumar said:   8 years ago
It's easy to understand. Thank you @Ashik.

Vinotha said:   8 years ago
Thank you all for the explanation.

Amarnaath said:   8 years ago
(6 * 10^3)*(5 * 10^5).

Values : 6*5 = 30(multiplication).
Powers : 5 + 3 = 8(adding).

Then the answer is (30 * 10^8).
(2)

Harshitha said:   8 years ago
(6*10^3)*(5*10^5)
= 6*5*(10^3+5).
= 30*10^8.
(1)

Ankit said:   8 years ago
a^m * b^n = a*b^m+n.

(6*5)*10^5+3 = 30*10^8.

Rajaneeesh said:   8 years ago
6*5 = 30.

5+3 = 8.

= 30*10^8.

Ela said:   9 years ago
6*5 = 30.

10^3*10^5 = 10^(3+5) = 10^8.

30*10^8.

Raji said:   9 years ago
Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication.

= 6*10^3*5*10^5 = 30*10^8.