Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
50 comments Page 2 of 5.
Sailu said:
1 decade ago
It's very easy anser.in multiply 6*5. If both bases r equal then powers must be added
So (6*5)*(10^3+10^5)=30*10^8
So (6*5)*(10^3+10^5)=30*10^8
MOHAMED SUBHAN said:
1 decade ago
6*5=30.
According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.
According to mathematical rule we have to add the powers so the powers 5+3=8 so the answer is 30x10^8.
Murali said:
1 decade ago
Simply, the numbers 6 and 5 normal multiplication (6*5=30).
In power the numbers has been added (3+5=8).
In power the numbers has been added (3+5=8).
Shailu said:
1 decade ago
6*5 = 30.
10 is common for both the values,
Powers are added.
10^3+5 = 10^8.
Total value = 30*10^8.
10 is common for both the values,
Powers are added.
10^3+5 = 10^8.
Total value = 30*10^8.
Lalan kr yadav said:
7 years ago
(6*10^3) * (5*10^5).
6*5*(10^3*10^5),
30*10^3+5,
30*10^8,
Or 3*10^9.
Then the answer is 30*10^8.
6*5*(10^3*10^5),
30*10^3+5,
30*10^8,
Or 3*10^9.
Then the answer is 30*10^8.
(2)
Santhosh kumar said:
1 decade ago
The power dissipated by a resistor of 10 ohm when a current of 2A passes through it is.
Lallan.k.puskar said:
1 decade ago
(6*10^3)*(5*10^5) = 6*5*10^3+5 = 30*10^8 Simple formula of use (a^n)*(a^m) = a^n+m.
Ganesh said:
1 decade ago
(6 x 10^3)=6000
(5 x 10^5)=500000
6000 x 500000 = 3000000000
3000000000 = 30x10^8
(5 x 10^5)=500000
6000 x 500000 = 3000000000
3000000000 = 30x10^8
Mahalakshmi said:
1 decade ago
Powers are added during multiplication so 6*5=30.
10^3+5=10^8 therefore 30*10^8.
10^3+5=10^8 therefore 30*10^8.
Nandu said:
1 decade ago
When we are multiplying of these numbers the powers of those numbers are added.
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