Electrical Engineering - Quantities and Units - Discussion

Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
3 × 108
30 × 108
300 × 109
3,000 × 107
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
50 comments Page 4 of 5.

Kunal said:   1 decade ago
In mathematical problem, the numbers are multiplied & powers are added.

Therefore, 6*5=30 & 10^3+5=8 so, 30*10^8.

Ezman Ezra said:   1 decade ago
6*10^3=6000 and 5*10^5=500000

When you multiply the answers you have 3000000000, there4 this can be written as

3*10^9 or 30*10^8

Tharanya said:   1 decade ago
(6*5)*(10^(5+3))=30*10^8

In mathematical problem, the numbers are multiplied, power are added and finally multiply both.

Kapil Dixit said:   1 decade ago
Because of both digits (6 and 5) are multiply directly with each other while the powers of multiplier will be additive.

Sailu said:   1 decade ago
It's very easy anser.in multiply 6*5. If both bases r equal then powers must be added

So (6*5)*(10^3+10^5)=30*10^8

Santosh said:   1 decade ago
I agree with ashik solution. Thank you ashik.

Debashis said:   1 decade ago
Its very easy that-6*5=30;

In exponent 10^(5+3)=10^8

So the ans is 30*10^8

Ganesh said:   1 decade ago
(6 x 10^3)=6000
(5 x 10^5)=500000
6000 x 500000 = 3000000000
3000000000 = 30x10^8

Mahalakshmi said:   1 decade ago
Powers are added during multiplication so 6*5=30.

10^3+5=10^8 therefore 30*10^8.

Pavi said:   1 decade ago
(6x10^3)(5x10^5)
(6x5x10^3+5)
(30x10^8)
So ans is Option B


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