Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
52 comments Page 2 of 6.
Dhivya said:
9 years ago
Simply the number 5 & 6 are multiplied & the powers are added.
(2)
Engineer majid said:
6 years ago
The power of number is add when multiplied so that's why.
(1)
Harshitha said:
10 years ago
(6*10^3)*(5*10^5)
= 6*5*(10^3+5).
= 30*10^8.
= 6*5*(10^3+5).
= 30*10^8.
(1)
Suresh k said:
9 years ago
Thank you for explaining the answer and providing the good shortcut method.
(1)
Shailu said:
1 decade ago
Is correct answer?
Raji said:
1 decade ago
Since the given numbers have a significant figure in each (6, 5), its product has two significant figures after multiplication.
= 6*10^3*5*10^5 = 30*10^8.
= 6*10^3*5*10^5 = 30*10^8.
Ela said:
1 decade ago
6*5 = 30.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
Rajaneeesh said:
1 decade ago
6*5 = 30.
5+3 = 8.
= 30*10^8.
5+3 = 8.
= 30*10^8.
Shailu said:
1 decade ago
6*5 = 30.
10 is common for both the values,
Powers are added.
10^3+5 = 10^8.
Total value = 30*10^8.
10 is common for both the values,
Powers are added.
10^3+5 = 10^8.
Total value = 30*10^8.
Santhosh kumar said:
1 decade ago
The power dissipated by a resistor of 10 ohm when a current of 2A passes through it is.
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