Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 17)
17.
A flaky aggregate is said to be elongated if its length is
equal to the mean size
twice the mean size
thrice the mean size
four times the mean size
five times the mean size.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
33 comments Page 3 of 4.

Viru kapoor said:   7 years ago
Option C is absolutely correct.

Flaky aggregates 3/5 = 0.6.
Elongated aggregates 9/5 = 1.8.
Any Flaky aggregate is said to be elongated if (0.6*3 = 1.8)
Which Means thrice.

Pavan said:   8 years ago
1.8 approximatly twice the mean dimension

Kanemozhe said:   8 years ago
Option B is correct because for flaky aggregates the size is considered for the width, not the length. Only when it comes to elongated aggregates, length is taken into account. And the question is regarding the length.

Jaydip said:   8 years ago
1.8 time mean six size.

Roy said:   8 years ago
Given answer is right according to SSC JE 2008 answer key. And the reason behind it according to me, the flaky aggregate is considered to their MEAN dimension and elongated aggregate is considered to their GREATER dimension.

Rajesh meena said:   8 years ago
Yes, the correct answer is C.

Minesh said:   8 years ago
I think C is the correct answer.

Vikas said:   9 years ago
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Shweta puri said:   9 years ago
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5=1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Sohan jangra said:   9 years ago
I agree, the right answer is B.


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