Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 17)
17.
A flaky aggregate is said to be elongated if its length is
equal to the mean size
twice the mean size
thrice the mean size
four times the mean size
five times the mean size.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
33 comments Page 2 of 4.

Ravi Kumar Poodi said:   4 years ago
It is clearly mentioned that the flaky aggregate, not the FLAKINESS INDEX is equating to the ELONGATION INDEX.

For a flaky aggregate, there should be a FI and EI.

Hence, FI= 3/5 of mean size and EI= 9/5 of mean size.

So the given answer is CORRECT----> option B.

Suraj said:   4 years ago
C is the correct answer.

Ablesh meena said:   5 years ago
C is the right option, The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Guddi Meena said:   5 years ago
It shoul be thrice.

Gaurav said:   5 years ago
Flaky aggregate .6 times mean dimensions.
Elongated aggregate 1.8 times mean dimensions.
So, Flaky aggregate is 3 times of elongated aggregate.

Narayan ch. Saha said:   6 years ago
Given answer is correct. Because there is no relation b/w flaky and elongation.

So 1.8~2 times.

Dheeraj said:   7 years ago
Can someone explain. Why it's twice?

Sandeep Suthar Hisar said:   7 years ago
Twice is the Correct answer because mean size is not 0.6 it is the length but we have calculated with respect to mean size so 9/5 is the correct answer.

Neelkanth said:   7 years ago
Option C is correct according to IS456.

Amol said:   7 years ago
Option B is correct because the answer will be from mean size.

9/5 is the mean size.


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