Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 4 (Q.No. 17)
17.
A flaky aggregate is said to be elongated if its length is
Discussion:
33 comments Page 1 of 4.
Sam said:
1 decade ago
It should be thrice as 3/5*3= 9/5.
RUPESH said:
1 decade ago
Flaky = 3/5*mean, i.e mean = 5/3*flaky.
Elongated = 9/5*mean.
= (9/5)*(5/3)*flaky = 3*flaky.
Hence, answer is thrice.
Elongated = 9/5*mean.
= (9/5)*(5/3)*flaky = 3*flaky.
Hence, answer is thrice.
Darshan h a said:
9 years ago
Aggregate is said to be flaky if its size is more than 9/5 of their mean size. i.e 1.8 times of their mean size which is approximately taken as 2 times in this problem.
Sohan jangra said:
9 years ago
I agree, the right answer is B.
Shweta puri said:
9 years ago
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5=1.8.
When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.
When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.
Vikas said:
8 years ago
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.
When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.
When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.
Minesh said:
8 years ago
I think C is the correct answer.
Rajesh meena said:
8 years ago
Yes, the correct answer is C.
Roy said:
8 years ago
Given answer is right according to SSC JE 2008 answer key. And the reason behind it according to me, the flaky aggregate is considered to their MEAN dimension and elongated aggregate is considered to their GREATER dimension.
Jaydip said:
8 years ago
1.8 time mean six size.
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