Civil Engineering - Concrete Technology - Discussion

17. 

A flaky aggregate is said to be elongated if its length is

[A]. equal to the mean size
[B]. twice the mean size
[C]. thrice the mean size
[D]. four times the mean size
[E]. five times the mean size.

Answer: Option B

Explanation:

No answer description available for this question.

Sam said: (Jun 17, 2015)  
It should be thrice as 3/5*3= 9/5.

Rupesh said: (Aug 18, 2015)  
Flaky = 3/5*mean, i.e mean = 5/3*flaky.

Elongated = 9/5*mean.

= (9/5)*(5/3)*flaky = 3*flaky.

Hence, answer is thrice.

Darshan H A said: (Jul 5, 2016)  
Aggregate is said to be flaky if its size is more than 9/5 of their mean size. i.e 1.8 times of their mean size which is approximately taken as 2 times in this problem.

Sohan Jangra said: (Feb 27, 2017)  
I agree, the right answer is B.

Shweta Puri said: (Mar 7, 2017)  
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5=1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Vikas said: (Mar 8, 2017)  
The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Minesh said: (Jun 21, 2017)  
I think C is the correct answer.

Rajesh Meena said: (Jul 28, 2017)  
Yes, the correct answer is C.

Roy said: (Aug 4, 2017)  
Given answer is right according to SSC JE 2008 answer key. And the reason behind it according to me, the flaky aggregate is considered to their MEAN dimension and elongated aggregate is considered to their GREATER dimension.

Jaydip said: (Aug 21, 2017)  
1.8 time mean six size.

Kanemozhe said: (Oct 30, 2017)  
Option B is correct because for flaky aggregates the size is considered for the width, not the length. Only when it comes to elongated aggregates, length is taken into account. And the question is regarding the length.

Pavan said: (Feb 15, 2018)  
1.8 approximatly twice the mean dimension

Viru Kapoor said: (Apr 3, 2018)  
Option C is absolutely correct.

Flaky aggregates 3/5 = 0.6.
Elongated aggregates 9/5 = 1.8.
Any Flaky aggregate is said to be elongated if (0.6*3 = 1.8)
Which Means thrice.

Amol said: (Sep 25, 2018)  
Option B is correct because the answer will be from mean size.

9/5 is the mean size.

Neelkanth said: (Nov 15, 2018)  
Option C is correct according to IS456.

Sandeep Suthar Hisar said: (Dec 22, 2018)  
Twice is the Correct answer because mean size is not 0.6 it is the length but we have calculated with respect to mean size so 9/5 is the correct answer.

Dheeraj said: (Dec 22, 2018)  
Can someone explain. Why it's twice?

Narayan Ch. Saha said: (Jan 20, 2020)  
Given answer is correct. Because there is no relation b/w flaky and elongation.

So 1.8~2 times.

Gaurav said: (Sep 21, 2020)  
Flaky aggregate .6 times mean dimensions.
Elongated aggregate 1.8 times mean dimensions.
So, Flaky aggregate is 3 times of elongated aggregate.

Guddi Meena said: (Sep 26, 2020)  
It shoul be thrice.

Ablesh Meena said: (Sep 26, 2020)  
C is the right option, The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

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