Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 4 (Q.No. 17)
17.
A flaky aggregate is said to be elongated if its length is
equal to the mean size
twice the mean size
thrice the mean size
four times the mean size
five times the mean size.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
33 comments Page 1 of 4.

Shubham Kumar said:   4 years ago
First of all. It's either 2 nor 3.

Flakiness and Elongation are not released to one other. Flakiness depends on the width of the aggregate and Elongation on length.

For Elongation, the length should be more than 1.8x of the mean size.
So exact the answer is 1.8,
1.8<2.

So, the nearest answer is 2.
Thank you.
(6)

Anees said:   4 years ago
The given answer is true.

Let me explain to you how.
Take mean size as reference( suppose 100mm).

Flaky aggregate has the least dimension less than (0.6)60% of the mean(i.e less than 60mm).
Elongated aggregate has a length of more than (1.8)180% of the mean(i.e more than 180mm), which is almost twice(1.8=2) of the MEAN. Please don't confuse it with thrice of flaky aggregate(0.6 x 3=1.80). Focus on the reference which is MEAN.
(5)

Irfan ali said:   4 years ago
3/5 for flaky
9/5 for elongated
So, 3 * 3/5 = 9/5.

So, the answer will be C.
(4)

Shabbir Ahmad said:   4 years ago
Let's suppose we have an aggregate with a mean size X.

So, for it to be elongated, its length should be greater than 1.8X and also for it to be flaky it's least dim should be less than 0.6X.

So, for aggregate to be both flaky and elongated, both conditions should be fulfilled and if the question says that the aggregate is flaky, so for it to be also elongated, its length should be 2X>1.8X.
(1)

Narayan ch. Saha said:   7 years ago
Given answer is correct. Because there is no relation b/w flaky and elongation.

So 1.8~2 times.

Dheeraj said:   8 years ago
Can someone explain. Why it's twice?

Gaurav said:   6 years ago
Flaky aggregate .6 times mean dimensions.
Elongated aggregate 1.8 times mean dimensions.
So, Flaky aggregate is 3 times of elongated aggregate.

Guddi Meena said:   6 years ago
It shoul be thrice.

Ablesh meena said:   6 years ago
C is the right option, The size of flaky aggregate is 3/5 =0.6 as well the size of an elongated particle is 9/5 = 1.8.

When we multiply 0.6 with 3 then the answer is 1.8 which is the size of an elongated particle as mention in the question. So option C is correct.

Suraj said:   6 years ago
C is the correct answer.


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