Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 22)
22.
For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50 kg cement, are:
Discussion:
22 comments Page 1 of 3.
Dikshant said:
1 decade ago
How the quantities are converted into liters?
Ram said:
1 decade ago
Volume of one beg cement = 0.035 cum.
Hence sand = 0.035*3 = 0.105 cum.
1 cum = 1000 lt.
So sand = 0.105*1000 = 105 lt.
& Aggregates = 105*2 = 210 lt.
Hence sand = 0.035*3 = 0.105 cum.
1 cum = 1000 lt.
So sand = 0.105*1000 = 105 lt.
& Aggregates = 105*2 = 210 lt.
Sim said:
1 decade ago
How do we convert litre to kg? Multiply by bulk density?
SURESH said:
1 decade ago
Kg and liter are equal, one gram = one milliliter.
Niharika said:
1 decade ago
How to convert volume to weight?
Vaibhav S said:
1 decade ago
Density = Mass/Volume.
Weight = Density*Volume*9.81.
Weight = Density*Volume*9.81.
Rohit said:
1 decade ago
1:3:6 is the proportion that he has asked.
Density = Mass/Volume.
Density of concrete = 1400 kg/m3.
Mass of cement = 50 kg (given).
1440 = 50/v, hence v = 0.035 m3.
Water = 0.035*3 = 0.105 m3.
Aggregates = 0.035*6 = 0.21 m3.
Cement:Sand:Aggregates = 0.035:0.105:0.21 (in m3).
Cement:Sand:Aggregates = 35:105:210 (in lts if multiplied above result with 1000 as 1 m3 = 1000 lts).
Density = Mass/Volume.
Density of concrete = 1400 kg/m3.
Mass of cement = 50 kg (given).
1440 = 50/v, hence v = 0.035 m3.
Water = 0.035*3 = 0.105 m3.
Aggregates = 0.035*6 = 0.21 m3.
Cement:Sand:Aggregates = 0.035:0.105:0.21 (in m3).
Cement:Sand:Aggregates = 35:105:210 (in lts if multiplied above result with 1000 as 1 m3 = 1000 lts).
Ramesh said:
1 decade ago
Density = Mass/Volume.
Weight = Density*Volume*9.81.
Why should we multiply with 9.81?
Weight = Density*Volume*9.81.
Why should we multiply with 9.81?
Bhavyasree said:
10 years ago
What its's bulk density?
Xai said:
10 years ago
@Rohit the density of concrete is 2400 kg/m3. Where did you get 1400 kg/m3?
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