Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 22)
22.
For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50 kg cement, are:
70 litres of sand and 120 litres of aggregates
70 kg of sand and 140 litres of aggregates
105 litres of sand and 140 litres of aggregates
105 litres of sand and 210 litres of aggregates
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 1 of 3.

Sabin said:   6 years ago
Guys I am a bit confused here. Isn't it kg and liters are equal? Then why not 50 kg of cement = 50 liters of cement?
(3)

Kapfoie said:   6 years ago
The Volume of 50kg bag of cement =35 litre,

Therefore;
Sand 35x3=105.
Aggregate 35x6=210.
(16)

Anil mahato said:   6 years ago
1kg = 0.7 liters.
50kg cement - 35liters.
3*50kgsand-150 * .7 = 105liter.
300kg aggregate-300*.7 = 210 liters.
(5)

Roy said:   8 years ago
Thanks @Baloch.

Your explanation is very simple & easy to understand.

Amal Zad said:   8 years ago
Thank you @Ram and @Bhavesh Pankar.

Pankoj said:   8 years ago
How to calculate quantity of water for this question?

Basudeb said:   8 years ago
Thanks to all.

Bhavesh Panker said:   8 years ago
50 kg of cement - 35 lit volume.
1:3:6
35 lit cement : 105 lit sand : 210 lit c.a.
(1)

Baloch said:   9 years ago
Clear cut solution:

A cement bag contains 35 liters of cement,

35 x 1 : 35 x 3 : 35 x 6.
= 35 : 105 : 210.
(7)

Dhanashree said:   9 years ago
Thank you all for providing the clear solution.


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