Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 22)
22.
For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50 kg cement, are:
70 litres of sand and 120 litres of aggregates
70 kg of sand and 140 litres of aggregates
105 litres of sand and 140 litres of aggregates
105 litres of sand and 210 litres of aggregates
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 1 of 3.

Rohit said:   1 decade ago
1:3:6 is the proportion that he has asked.

Density = Mass/Volume.

Density of concrete = 1400 kg/m3.

Mass of cement = 50 kg (given).

1440 = 50/v, hence v = 0.035 m3.

Water = 0.035*3 = 0.105 m3.

Aggregates = 0.035*6 = 0.21 m3.

Cement:Sand:Aggregates = 0.035:0.105:0.21 (in m3).

Cement:Sand:Aggregates = 35:105:210 (in lts if multiplied above result with 1000 as 1 m3 = 1000 lts).

Ram said:   1 decade ago
Volume of one beg cement = 0.035 cum.

Hence sand = 0.035*3 = 0.105 cum.

1 cum = 1000 lt.

So sand = 0.105*1000 = 105 lt.

& Aggregates = 105*2 = 210 lt.

Sabin said:   6 years ago
Guys I am a bit confused here. Isn't it kg and liters are equal? Then why not 50 kg of cement = 50 liters of cement?
(3)

Anil mahato said:   6 years ago
1kg = 0.7 liters.
50kg cement - 35liters.
3*50kgsand-150 * .7 = 105liter.
300kg aggregate-300*.7 = 210 liters.
(5)

Baloch said:   9 years ago
Clear cut solution:

A cement bag contains 35 liters of cement,

35 x 1 : 35 x 3 : 35 x 6.
= 35 : 105 : 210.
(7)

Kapfoie said:   6 years ago
The Volume of 50kg bag of cement =35 litre,

Therefore;
Sand 35x3=105.
Aggregate 35x6=210.
(16)

Ramesh said:   1 decade ago
Density = Mass/Volume.

Weight = Density*Volume*9.81.

Why should we multiply with 9.81?

Bhavesh Panker said:   8 years ago
50 kg of cement - 35 lit volume.
1:3:6
35 lit cement : 105 lit sand : 210 lit c.a.
(1)

Xai said:   10 years ago
@Rohit the density of concrete is 2400 kg/m3. Where did you get 1400 kg/m3?

Roy said:   8 years ago
Thanks @Baloch.

Your explanation is very simple & easy to understand.


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