Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 22)
22.
For batching 1:3:6 concrete mix by volume, the ingredients required per bag of 50 kg cement, are:
Discussion:
22 comments Page 2 of 3.
Shrikant said:
10 years ago
Its a density of cement.
Antil said:
10 years ago
This is not a density of concrete. It is density of cement = 1440 kg/m3.
Dhanashree said:
9 years ago
Thank you all for providing the clear solution.
Baloch said:
9 years ago
Clear cut solution:
A cement bag contains 35 liters of cement,
35 x 1 : 35 x 3 : 35 x 6.
= 35 : 105 : 210.
A cement bag contains 35 liters of cement,
35 x 1 : 35 x 3 : 35 x 6.
= 35 : 105 : 210.
(7)
Bhavesh Panker said:
8 years ago
50 kg of cement - 35 lit volume.
1:3:6
35 lit cement : 105 lit sand : 210 lit c.a.
1:3:6
35 lit cement : 105 lit sand : 210 lit c.a.
(1)
Basudeb said:
8 years ago
Thanks to all.
Pankoj said:
8 years ago
How to calculate quantity of water for this question?
Amal Zad said:
8 years ago
Thank you @Ram and @Bhavesh Pankar.
Roy said:
8 years ago
Thanks @Baloch.
Your explanation is very simple & easy to understand.
Your explanation is very simple & easy to understand.
Anil mahato said:
6 years ago
1kg = 0.7 liters.
50kg cement - 35liters.
3*50kgsand-150 * .7 = 105liter.
300kg aggregate-300*.7 = 210 liters.
50kg cement - 35liters.
3*50kgsand-150 * .7 = 105liter.
300kg aggregate-300*.7 = 210 liters.
(5)
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