Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
                   
                                       
                                3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
 
                                    Answer: Option
                                                    Explanation:
                                                Let the actual distance travelled be x km.
| Then, | x | = | x + 20 | 
| 10 | 14 | 
 14x = 10x + 200
 4x = 200
 x = 50 km.
Discussion:
174 comments Page 9 of 18.
                
                        Reality Check said: 
                         
                        1 decade ago
                
                Walking at 14 km/h or even 10 km/h is. Unrealistic.
                
                        RAJ ARJ said: 
                         
                        1 decade ago
                
                10km/hr-------------->x km.
14km/hr-------------->x+20 km.
So cross multiplication,
10(x+20) = 14x.
10x+200 =14x.
200 = 14x-10x.
200 = 4x.
x = 50 km.
                14km/hr-------------->x+20 km.
So cross multiplication,
10(x+20) = 14x.
10x+200 =14x.
200 = 14x-10x.
200 = 4x.
x = 50 km.
                        Sahil said: 
                         
                        1 decade ago
                
                Speed 40% of x = 20.
Solving x =50.
                Solving x =50.
                        Santoooosh said: 
                         
                        1 decade ago
                
                It is very clear. The time in both the cases is same that is 5 hrs.
T = 5;
Now the distance travelled by him at a speed of 10 kmph is x/10 in 5 hrs.
Similarly the distance travelled by him at a speed of 14 kmph is (x+20)/14 in 5 hrs.
Form that we can say that x/10 = 5, and (x+20)/14 = 5;
From the above x/10 = (x+20)/14.
Solve this you will get the answer.
                T = 5;
Now the distance travelled by him at a speed of 10 kmph is x/10 in 5 hrs.
Similarly the distance travelled by him at a speed of 14 kmph is (x+20)/14 in 5 hrs.
Form that we can say that x/10 = 5, and (x+20)/14 = 5;
From the above x/10 = (x+20)/14.
Solve this you will get the answer.
                        VIJAY said: 
                         
                        1 decade ago
                
                5*10 = 50 because t = 5 and Distance = Speed*Time.
                
                        Suman said: 
                         
                        1 decade ago
                
                14x-10x = 20.
4x = 20.
x = 5.
Actual distance = 10*5 = 50.
                4x = 20.
x = 5.
Actual distance = 10*5 = 50.
                        Mallikarjun said: 
                         
                        1 decade ago
                
                Difference of speed 14-10 = 4.
Therefore 4 km ----> 20.
So 10 km to travels 50 km.
                Therefore 4 km ----> 20.
So 10 km to travels 50 km.
                        Ketan said: 
                         
                        1 decade ago
                
                Here time is never given.
So consider man named.
Ashok walk with speed 10 km/hr, he travel for next 2 hour so distance he cover is 20 km.
2nd person named.
Madhu walk with speed 14 km/hr, he also travel for 2 hour so distance he cover is 28 km.
Now Madhu travel more 20 km wit speed 14 km/hr. So we subtract that 20 km from distance he travel in 2 hour.
= 28-20 = 8 km.
It means if we consider time 2 hour. Which is not given, so the answer will be 8 km?
Is it true?
                So consider man named.
Ashok walk with speed 10 km/hr, he travel for next 2 hour so distance he cover is 20 km.
2nd person named.
Madhu walk with speed 14 km/hr, he also travel for 2 hour so distance he cover is 28 km.
Now Madhu travel more 20 km wit speed 14 km/hr. So we subtract that 20 km from distance he travel in 2 hour.
= 28-20 = 8 km.
It means if we consider time 2 hour. Which is not given, so the answer will be 8 km?
Is it true?
                        Manish nair said: 
                         
                        1 decade ago
                
                It came by this formula S = D/T (Speed = Distance/Time).
Here we take this formula such as:
T = D/S.
Let consider actual distance x km.
T = x/10.....(1).
T = x+20/14.....(2).
Taking both the times together we get from (1) and (2).
x/10 = x+20/14.
14x = 10x+200.
4x = 200.
x = 50km.
Hope you get it now.
                Here we take this formula such as:
T = D/S.
Let consider actual distance x km.
T = x/10.....(1).
T = x+20/14.....(2).
Taking both the times together we get from (1) and (2).
x/10 = x+20/14.
14x = 10x+200.
4x = 200.
x = 50km.
Hope you get it now.
                        Guna said: 
                         
                        1 decade ago
                
                I can't understand please explain clearly.
                Post your comments here:
 
            
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