Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 8 of 18.
Sohail said:
1 decade ago
We can do this in simple unitary method; like,
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
Gaurav Ralhan said:
1 decade ago
But it is not written that time instance is same.
Bhat said:
1 decade ago
Difference between distance i.e. 14-10 = 4.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Keerthi said:
1 decade ago
First the question is find actual distance.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
Jeeva said:
1 decade ago
Extra 4kmhr------20km more.
So 1kmhr------ ?
20*1/4 so = 5.
so 10km*5 = 50.
So 1kmhr------ ?
20*1/4 so = 5.
so 10km*5 = 50.
Santoshganur1@gmail.com said:
1 decade ago
Actual distance = xkm.
Simply a person walks 14 km instead 10 km,
So 14-10 = 4.
10*20 = 200.
200/4 = 50;
Simply a person walks 14 km instead 10 km,
So 14-10 = 4.
10*20 = 200.
200/4 = 50;
Kiran said:
1 decade ago
If this person walks 10km then he walks xkm.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
Bill said:
1 decade ago
14-10 = 4km/hr more at 14, 20km/hr extra distance.
20/4 = 5hrs.
5*14 = 70 is the answer.
20/4 = 5hrs.
5*14 = 70 is the answer.
Siva Nandi Reddy said:
1 decade ago
The difference between the two speeds is 20 km in the above question.
4km/h----------20km.
So 10km/h---------?
Cross multiplication so we get 50 km/h.
4km/h----------20km.
So 10km/h---------?
Cross multiplication so we get 50 km/h.
Sunil said:
1 decade ago
Time in this solution is 1 hr since it is km per hour and then x/10 would be for 1 hr and x+20/14 would also be for 1 hr.
Hence they can be equated. So this in other words is a unitary method.
Hence they can be equated. So this in other words is a unitary method.
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