Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
171 comments Page 8 of 18.
Atiya said:
9 years ago
Thanks for all your hard work and solution.
Ziyauddin said:
9 years ago
@Gowtham.
Thanks, you expressed clearly.
Thanks, you expressed clearly.
Sidzwozz said:
9 years ago
@Ilesh.
Explained very well.
Explained very well.
Raj said:
9 years ago
Here time is constant = t;
No old speed = 10 new speed 10*14/10.
D-14/10d = 20.
D = 20*10/4 = 50 km.
No old speed = 10 new speed 10*14/10.
D-14/10d = 20.
D = 20*10/4 = 50 km.
Feroz said:
9 years ago
14 - 10 = 4,
20/4 = 5,
5 * 10 = 50.
20/4 = 5,
5 * 10 = 50.
Jayant said:
9 years ago
@All.
Thanks, you all expressed clearly.
Thanks, you all expressed clearly.
Krishna Sharma said:
9 years ago
Please solve this.
While covering a distance of 60 km, A takes 4 hours more than B. If A doubles its speed, A took 2 hours less than B. Find the walking speed using a simultaneous equation or quadratic equation.
While covering a distance of 60 km, A takes 4 hours more than B. If A doubles its speed, A took 2 hours less than B. Find the walking speed using a simultaneous equation or quadratic equation.
Satya said:
9 years ago
Given;
14kmph at 20 km MORE i.e extra speed.
So we can write it as 4 kmph -20.,
Each km 20÷4 = 5.
Hence 10 * 5 = 50.
14kmph at 20 km MORE i.e extra speed.
So we can write it as 4 kmph -20.,
Each km 20÷4 = 5.
Hence 10 * 5 = 50.
Vikash said:
9 years ago
Let actual distance x km.
Actual speed =10 kmph T1 = ?
Man walk 20 km more,
Distance = x + 20.
Speed = 14 kmph T2 = ?
Now T1 = T2.
D1/S1 = D2/S2.
x/10 = x + 20/14 after solving x (actual distance) = 50 km answer.
Actual speed =10 kmph T1 = ?
Man walk 20 km more,
Distance = x + 20.
Speed = 14 kmph T2 = ?
Now T1 = T2.
D1/S1 = D2/S2.
x/10 = x + 20/14 after solving x (actual distance) = 50 km answer.
Sambath said:
8 years ago
@Gowtham, @Ilesh.
Both are explained very well. Thank you.
Both are explained very well. Thank you.
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