Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
172 comments Page 4 of 18.
Tanay said:
1 decade ago
In 4 kmph he walk more 20 km.
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
Laxman said:
1 decade ago
The actual distance should be the 10hr/km i.e. (50km ) + extra 20KM = 70 km?
Anjith said:
1 decade ago
Hi,
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
Sohail said:
1 decade ago
We can do this in simple unitary method; like,
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
If the man travels at the speed of 14 km/hr he covers 20 extra km than if he travels at 10 km/hr.
Therefore we can see this extra 4 km/hr speed helps him to cover 20 km.
Now we can write in:
4 km/hr speed he covers 20 km;
1 km/hr speed he cover 20/4 km;
Now in (original speed) 10 km/hr speed he covers 20/4 x 10 = 50 km.
Gaurav Ralhan said:
1 decade ago
But it is not written that time instance is same.
Bhat said:
1 decade ago
Difference between distance i.e. 14-10 = 4.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Keerthi said:
1 decade ago
First the question is find actual distance.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
Jeeva said:
1 decade ago
Extra 4kmhr------20km more.
So 1kmhr------ ?
20*1/4 so = 5.
so 10km*5 = 50.
So 1kmhr------ ?
20*1/4 so = 5.
so 10km*5 = 50.
Santoshganur1@gmail.com said:
1 decade ago
Actual distance = xkm.
Simply a person walks 14 km instead 10 km,
So 14-10 = 4.
10*20 = 200.
200/4 = 50;
Simply a person walks 14 km instead 10 km,
So 14-10 = 4.
10*20 = 200.
200/4 = 50;
Kiran said:
1 decade ago
If this person walks 10km then he walks xkm.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
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