Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
Then, | x | = | x + 20 |
10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
171 comments Page 16 of 18.
Sriya said:
3 years ago
Thanks for your explanation, it's easy to understand @Gowtham.
(13)
Habtamu dese said:
2 years ago
Good to understand. Thanks everyone for explaining the answer.
(8)
Gaurav Raghav said:
2 years ago
Let the actual speed be x.
Let the time be y.
Distance = Speed * time
Therefore,
X= 10y.
But, now he would have travelled 20 km more if the speed was 14km/hr.
therefore,
14x= y+20.
Subtracting both equations,
14x = y+20,
10x = y.
we get;
4x = 20,
x = 5.
Put y in the equation
10 * 5 = 50 Kms.
Verify it by putting 5 in both equations.
Let the time be y.
Distance = Speed * time
Therefore,
X= 10y.
But, now he would have travelled 20 km more if the speed was 14km/hr.
therefore,
14x= y+20.
Subtracting both equations,
14x = y+20,
10x = y.
we get;
4x = 20,
x = 5.
Put y in the equation
10 * 5 = 50 Kms.
Verify it by putting 5 in both equations.
(9)
Aryan said:
2 years ago
@All,
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
(10)
Pulyala ajith kumar said:
2 years ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(55)
Meghan Desai said:
2 years ago
Let
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.
FORMULA: Distance = Speed x Time.
1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).
Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.
Actual distance (at actual speed):-
10kmphx 5hrs = 50km.
That's the answer.
Actual distance is 'X' - (at 10kmph),
Distance afterwards is 'X+20' - (at 14kmph).
Also, the time be 'Y'.
FORMULA: Distance = Speed x Time.
1. X = 10Y ---> (a)
2. X+20 = 14Y
X = 14Y-20 ---> (b).
Comparing a&b we have;
10Y = 14Y-20
So, 14Y-10Y = 20;
and, Y = 5hrs.
Actual distance (at actual speed):-
10kmphx 5hrs = 50km.
That's the answer.
(30)
Chahat said:
2 years ago
Thanks, everyone for explaining.
(20)
Tariq said:
2 years ago
Given:
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
S1= 14km/h
S2= 10km/h
D1= 20km
D2=?
Solution:
We know that; (Distance= Speed * Time)
We first need to know the time taken,
By putting values:
20km = 14km/h (s1) - 10km/h (s2)
20km = 4 km/h,
20/4 = 5.
So the time (T) is 5.
Similarly, putting values we get;
D2 (actual distance)= 10km/h (actual speed) * 5 (time).
Distance= 10*5km.
Actual distance= 50km.
(131)
MO HASAN said:
2 years ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(94)
Vishal said:
1 year ago
Why t in both the equation is same?
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
(12)
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