Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 14 of 18.
Manish Kumar said:
8 years ago
Hello friends.
The person walks 14kmph instead of 10 km that means his original speed is 10kmph.
By walking 4kmph extra speed he covers 20 km.
That means for 1kmph he will cover 5 km.
Then for 10kmph, he will go 50 km. It's so simple.
The person walks 14kmph instead of 10 km that means his original speed is 10kmph.
By walking 4kmph extra speed he covers 20 km.
That means for 1kmph he will cover 5 km.
Then for 10kmph, he will go 50 km. It's so simple.
Vignesh Strive said:
8 years ago
Thanks for easy explanation @Gowtham.
Sonu said:
8 years ago
Given data both are speed rate 1h. First take 1h =x/10, and second take 1h=x+20/14. Both are take time 1hour.
Chetan said:
8 years ago
Thank you @Ilesh.
Varun said:
8 years ago
I can't catch the concept, since he increased his speed from 10 to 14 so actual distance would have been 14*5=70.
Manish said:
8 years ago
If he travels xkm.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
Vishnu said:
7 years ago
Hi, friends.
Here both times are equal for traveling x, and x+20 so x/10 =x+20/14.
Here both times are equal for traveling x, and x+20 so x/10 =x+20/14.
Manu M said:
7 years ago
@All.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
Krishna sai thota said:
7 years ago
He walks 14k/h instead 10k/h.
So he covered 20km in 20÷(14-10)= 5 hr.
So, D= 10* 5 = 50 Km.
So he covered 20km in 20÷(14-10)= 5 hr.
So, D= 10* 5 = 50 Km.
Rakesh said:
7 years ago
Why did you take the same value in both cases? Please explain.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers