Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 13 of 18.
Hroshid said:
9 years ago
Suppose walking time of this man = t.
So the walking distance for 14kmph = 14 * t = 14t,
and the actual walking distance=10 * t = 10t.
So as question, we can say 14t-10t = 20km # 4t=20 #t=5.
So the actual distance travel by him = 10 * 5 = 50km.
Hope all of you understand.
So the walking distance for 14kmph = 14 * t = 14t,
and the actual walking distance=10 * t = 10t.
So as question, we can say 14t-10t = 20km # 4t=20 #t=5.
So the actual distance travel by him = 10 * 5 = 50km.
Hope all of you understand.
Tejadeep said:
8 years ago
Why you take x+20 can anyone explain it? Please.
Nandu said:
8 years ago
S1 : S2 = d1 : d2 = 14 : 10,
Diff 4 parts 20,
1 part 5,
Initially at 10 speed = 10 * 5=50.
Diff 4 parts 20,
1 part 5,
Initially at 10 speed = 10 * 5=50.
Dev said:
8 years ago
I am not getting this, please anyone help me.
Souvik said:
8 years ago
To take time as x is the easiest way to solve.
Anoop Krishna said:
8 years ago
Hey, friends.
This is the easiest way of thinking.
Let the distance travelled by walking at the speed of 10km/h be x.
Then the distance travelled by walking at the speed of 14km/h will be x+20(according to the question).
so, 14=x+20,
10=x.
Cross multiply and find the value of x.
This is the easiest way of thinking.
Let the distance travelled by walking at the speed of 10km/h be x.
Then the distance travelled by walking at the speed of 14km/h will be x+20(according to the question).
so, 14=x+20,
10=x.
Cross multiply and find the value of x.
Parikshit said:
8 years ago
If 10kmph will cover x distance than 14 will cover it faster. But why here 20 km is added to 14kmph distance. How can it be possible?
Surin said:
8 years ago
14:10
7:5
2 difference = 20,
So 20/2 = 10.
5*10 = 50 ans.
7:5
2 difference = 20,
So 20/2 = 10.
5*10 = 50 ans.
Mayur jaiwal said:
8 years ago
14-10 = 4km,
10*20 = 200,
200%4 = 50.
10*20 = 200,
200%4 = 50.
Zainabfatima said:
8 years ago
Your explanation is very clear. Thank you so much @Ilesh.
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