Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Answer: Option
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
 |
3x | = 27 or x = |  |
27 x 16 |  |
= 144. |
| 16 | 3 |
| Birds killed by A = | 5x | = | |
5 | x 144 | |
= 30. |
| 24 | 24 |
Discussion:
41 comments Page 5 of 5.
Abhishek Tripathi said:
4 weeks ago
• B kills once in 2 shots ⇒ B’s hit probability = 1/2. So miss probability = 1 - 1/2 = 1/2.
• B has missed 27 times. Since each shot has a 1/2 chance to miss, the number of shots B fired is
shots by B = 27/(1/2)= 27*2 = 54.
• A fires 5 shots for every 3 shots of B. So when B fired 54 shots, A fired
shots by A = (5/3)*54 = 5*18 = 90.
• A kills once in 3 shots, so the number of kills by A = 90/3=30.
Answer: 30 birds (option A).
• B has missed 27 times. Since each shot has a 1/2 chance to miss, the number of shots B fired is
shots by B = 27/(1/2)= 27*2 = 54.
• A fires 5 shots for every 3 shots of B. So when B fired 54 shots, A fired
shots by A = (5/3)*54 = 5*18 = 90.
• A kills once in 3 shots, so the number of kills by A = 90/3=30.
Answer: 30 birds (option A).
(1)
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