Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
30 birds
60 birds
72 birds
90 birds
Answer: Option
Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8

Shots fired by B = 3 x
8

Killing shots by A = 1 of 5 x = 5 x
3 8 24

Shots missed by B = 1 of 3 x = 3 x
2 8 16

3x = 27 or x = 27 x 16 = 144.
16 3

Birds killed by A = 5x = 5 x 144 = 30.
24 24

Discussion:
40 comments Page 4 of 4.

Sapna said:   7 years ago
Thanks @Sudip.
(1)

Yamini Dhanasekar said:   7 years ago
Another way of solving this question by logic is,
B -27 times failed,it indicates 27 times succeeded.(given in question, kills once in 2 shots)
So totally,27+27=54 shots.
A fires 5 shots for b's 3.
A --------- B
5 --------- 3
?? --------- 54.

A=54 * 5/3=90 shots.
A has 90 shots,
A kills once in 3 shots, so 90/3 =30 birds.
(37)

Arun Congo said:   6 years ago
If A Shoot 5, B will shoot 3.

Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.

In question, we have 27 fails for B.

So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.
(8)

Ganga said:   4 years ago
B missed 27 times. Hence, B fired,
27 * 2 = 54 shots.

Therefore, the number of shots fired by
A = (54/3)*5,
= 90.
Therefore, the number of birds killed by;
A = 90*(1/3),
= 30.
(40)

Kaviya said:   3 years ago
Thanks for explaining @Smirthi.
(3)

Mufassil said:   3 years ago
Thanks for explaining the answer @Hary.
(2)

Sonu said:   2 years ago
Thanks @Sudip.
(1)

Sai said:   2 years ago
Can anyone please explain the question?
(7)

Renitha said:   11 months ago
Total short by B = 2 * 27 = 54,
Total short by A = 5/3 * 57 ==>5*18==>90,
killed by A = 90/3==>30,
A killed 30 birds.
(9)

Deepali said:   1 month ago
Every time B fires 3 shots, A fires 5 shots
That’s a firing ratio: A: B = 5 : 3, every time B fires 3, A fires 5.
But B, from 3 shots, he misses 1 shot every time he fires and kills 2, so the total he misses is 27.
In simple language, B misses 1 shots and kills 2, We have given no of shots he missed, but it doesn't include the shots he used to kill, which is 2.
To get the total no of shots of B, 27x2=54 shots.
To calculate A shots, which is 5:3, 54/3=18 times A fired, and 1 time firing consists of 5 shots.
So, 18 x 5 = 90.
The total no of shots A fired is 90, kills once in 3 shots, so 90/3= 60.
(1)


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