Aptitude - Simplification - Discussion

B kills once in 2 shots.

No. of failure shots = 1.

No. of succeeded shots = 1.

When no. of failure shots = 27 then no. of succeeded shots = 27,

So, total no. of shots by B = 27+27 = 54.

When B shoots 3 shot then A shoots 5 shots.

So, When B shoots 1 shot then A shoots 5/3 shot.

So, When B shoots 54 shot then A shoots 54*5/3 = 90 shots.

When A shoots 3 it killed 1.

So, when A shoots 90 it killed = 90/3 = 30.

The ratio of no.of shots by A to the no.of shots by B is 5:3.

Let the actual shots of A and B be 5x and 3x respectively.

B kills once in 2 shots means one shot of B gets success and another shot gets failure.

Total shots = 27 failed shots + 27 successful shots = 54.

That is 3x = 54.

x = (54/3) = 18.

A's total shots = 5x = 5(18) = 90.

A kills once in 3 shots means A's 2 shots get failed and 1 shot.

Achieves the target (kills the bird).

So, A has killed (90/3) = 30 birds.

A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given).

Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).

How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one?

A fires 5 shots and kills one in 3.

Therefore effective short by A = 3/5.

Similarly B = 2/3.

Also 3/5A = 2/3B.

Now, the no of birds killed by B in 27 shots would be 27*2/3 = 18.

When B kills 18 birds. No of birds killed by A = 18*5/3 = 30.

Can anybody tell me if I am doing it right?

Both A and B stand side by side and shoot at the same time. 5 bullets com out of A's gun and 3 bullets come out of B's gun. So the total no of bullets fired at once is 8.

Its given that A kills one in 3 shots and B kills one in 2 shots. Its also given that B misses 27 times.

As B Misses 27 times and kills one in two shots, the total bullets fired by B is 27*2 = 54.

We know that 3 bullets came out of B'S gun when he shot once.

So the no of times B shot is 54/3 = 18.

Also the no of bullets came out of A is 5 when he shot once and since both A and B shot same no of times i.e.18 times, so the total no of bullets came out of A's gun is 5*18 = 90 bullets.

As A killed one in three bullets, the total no of birds killed by A is 90/3 = 30.

Let A and B be 5x, 3x.

If x = 1, A = 5 B = 3,

If x = 2, A = 10 B = 6,

3x = 54,

=> x = 18,

Total number of shots of A = 5x

= 5 * 18 = 90,

Number of succeeding shots of A = 1/3 * total shots of A

= 1/3 * 90 = 30.

A:B=5:3.

27 shots fired failed by B.

Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.

A/B= 5/3.

Therefore A/54=5/3, hence total shorts of A = 90.

Probability that A hits = 1/3;

Therefore total shorts hit = 90 * 1/3 = 30.

Any other simple method to solve this problem?

Thank you @Naddy.