Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 8 of 36.
Bhaskar Gairola said:
1 decade ago
Let C.P. of 1 article =1.
C.P. of x articles = x.
S.P. of x articles = 1.25x.
Given S.P. of x articales = C.P. of 20 articles.
1.25x = 20.
x=16.
C.P. of x articles = x.
S.P. of x articles = 1.25x.
Given S.P. of x articales = C.P. of 20 articles.
1.25x = 20.
x=16.
(1)
Sri Ram Kumar said:
1 decade ago
I got the answer but I am not sure the solution is correct any suggestions please:
C.P of 20 articles=125% of S.P of X articles.
20=125/100 S.P of X articles(here we have to assume C.P of one article to be 1 rupee).
20*100/125=16.
C.P of 20 articles=125% of S.P of X articles.
20=125/100 S.P of X articles(here we have to assume C.P of one article to be 1 rupee).
20*100/125=16.
Manish said:
1 decade ago
Given C.P of 20 articles = S.P of X articles,
If we consider C.P of 1 article is Rs.1 the S.P of X = 20. from this S.P of 1 articles will be 20/X.
So (20/X - 1)/1*100 =25 which give 16 as a Answer .
If we consider C.P of 1 article is Rs.1 the S.P of X = 20. from this S.P of 1 articles will be 20/X.
So (20/X - 1)/1*100 =25 which give 16 as a Answer .
Sumit said:
1 decade ago
Let, C.P of 20 articles = S.P of x articles = y.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
(1)
Sonu said:
1 decade ago
Its very simple to find out the value of x.
The cost price of 20 articles = the selling price of x articles. Here profit is 25% So,
20 = x*(125/100).
2000/125 = x.
So x = 16.
The cost price of 20 articles = the selling price of x articles. Here profit is 25% So,
20 = x*(125/100).
2000/125 = x.
So x = 16.
Suku Driver said:
1 decade ago
1 step answer:
(1/(20-x)) *100 = 25%.
Simplify, and gets x=16.
Note: (1/(20-x)) is the fraction in terms of Articles.
(1/(20-x)) *100 = 25%.
Simplify, and gets x=16.
Note: (1/(20-x)) is the fraction in terms of Articles.
Kailash said:
1 decade ago
Let 1 article price is p.
Then 20 article price will be 20p.
x article price will be = xp.
As per question ...selling price of x articles = sp = 20p.
Cost price of x articles = cp = xp.
=> Gain g = sp - cp= 20p-xp = (20-x)p.
%of gain = {((20-x)p) *100}/xp.
But given Gain = 25%.
=> {((20-x)p) *100}/xp =25.
=> {((20-x)p) *100} =25*xp.
=> {(20-x) *100} = 25*x.
=> {(20-x) *} = (25*x)/100 = x/4.
=> 20 = (x/4.)+x = (5/4)x.
=>x=16.
So here the value of x is 16.
Then 20 article price will be 20p.
x article price will be = xp.
As per question ...selling price of x articles = sp = 20p.
Cost price of x articles = cp = xp.
=> Gain g = sp - cp= 20p-xp = (20-x)p.
%of gain = {((20-x)p) *100}/xp.
But given Gain = 25%.
=> {((20-x)p) *100}/xp =25.
=> {((20-x)p) *100} =25*xp.
=> {(20-x) *100} = 25*x.
=> {(20-x) *} = (25*x)/100 = x/4.
=> 20 = (x/4.)+x = (5/4)x.
=>x=16.
So here the value of x is 16.
Youth said:
1 decade ago
Hey @Kailash I know that you know the answer, but if we do that much lengthy it will take more time. Think about shortcut yaar please. Thank you for giving explanation.
Avi said:
1 decade ago
simplest method:
Here give 25% profit means 125/100 ok means 5/4 ratio so 20 article.
1st type 4/5*20=16.
2nd type 5/4 do multiply by 4 both because be need 20 article so get 16 sp.
Here give 25% profit means 125/100 ok means 5/4 ratio so 20 article.
1st type 4/5*20=16.
2nd type 5/4 do multiply by 4 both because be need 20 article so get 16 sp.
Chandan kumar said:
1 decade ago
We can also use formula this type of question.
If the cost price of M article is equal to selling price N article
then.
%gain/loss = (M-N/N)*100.
If M>N it is gain% if M<N it loss%.
Solution:- 25 = (20-X/x)*100.
25x = 2000-100x.
125x = 2000.
x = 2000/125.
x = 16.
If the cost price of M article is equal to selling price N article
then.
%gain/loss = (M-N/N)*100.
If M>N it is gain% if M<N it loss%.
Solution:- 25 = (20-X/x)*100.
25x = 2000-100x.
125x = 2000.
x = 2000/125.
x = 16.
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