Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
![]() |
![]() |
20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 1 of 36.
Ashutosh Khadka said:
2 years ago
Here is logical method:
25% means 1/4.
Now find the number which is directly divided by 4 in the option.
There is only one option which is directly divided by 4.
Therefore Option is (B) 16.
25% means 1/4.
Now find the number which is directly divided by 4 in the option.
There is only one option which is directly divided by 4.
Therefore Option is (B) 16.
(150)
Pranav said:
2 years ago
Given:
Cost price of 20 articles = Selling price of x articles
20 * C = x * S.
Profit is 25%, which means the selling price is 125% of the cost price:
S = 1.25 * C.
Substitute the value of S from the second equation into the first equation:
20 * C = x * (1.25 * C).
Now, solve for x:
x = (20 * C)/(1.25 * C),
x = 20/1.25,
x = 16.
Cost price of 20 articles = Selling price of x articles
20 * C = x * S.
Profit is 25%, which means the selling price is 125% of the cost price:
S = 1.25 * C.
Substitute the value of S from the second equation into the first equation:
20 * C = x * (1.25 * C).
Now, solve for x:
x = (20 * C)/(1.25 * C),
x = 20/1.25,
x = 16.
(133)
Err said:
2 years ago
20 C. P = x S. P.
C.P = x/20 SP--->(1)
Gain = 25%.
S. P = 125% of CP.
S. P= 125/100 * CP.
Substitute CP value as (1)
x = 16.
C.P = x/20 SP--->(1)
Gain = 25%.
S. P = 125% of CP.
S. P= 125/100 * CP.
Substitute CP value as (1)
x = 16.
(115)
Surbhi garg said:
3 years ago
CP of 20 articles = SP of x article.
Profit% = 25.
Let's CP = 100rs.
SP = 125.
CP of 20 articles = SP of x article.
20*100 = 125 * x.
x =2000/125,
x=16.
Profit% = 25.
Let's CP = 100rs.
SP = 125.
CP of 20 articles = SP of x article.
20*100 = 125 * x.
x =2000/125,
x=16.
(63)
Naveen said:
2 years ago
Let, the cost of 1 article is 1.
Then CP of articles = 20.
According to the statement, CP of articles is equal to the SP of x.
So, SP of x =20.
And there is a 25% profit in this SP.
Then CP of x.
125% of x = 20.
Here x is CP.
X = 16.
Then CP of articles = 20.
According to the statement, CP of articles is equal to the SP of x.
So, SP of x =20.
And there is a 25% profit in this SP.
Then CP of x.
125% of x = 20.
Here x is CP.
X = 16.
(53)
Shal said:
1 year ago
Let cp=100 for 20 articles.
Profit=25%
Therefore, sp = 125.
Now for 125 - 20 articles,
100 - how many articles?
20 x 100/125 = 16.
So, 16 is the answer.
Profit=25%
Therefore, sp = 125.
Now for 125 - 20 articles,
100 - how many articles?
20 x 100/125 = 16.
So, 16 is the answer.
(50)
Prince said:
2 years ago
20 CP = x SP
CP/SP = x/20.
profit % =25 (given)
profit % = (SP-CP/CP) * 100 ---> FORMULA.
Putting the value in the formula.
(20 - x/ x) * 100 = 25.
Solve for x.
80 - 4x/x = 1,
80 = 5x,
x = 16 ans.
CP/SP = x/20.
profit % =25 (given)
profit % = (SP-CP/CP) * 100 ---> FORMULA.
Putting the value in the formula.
(20 - x/ x) * 100 = 25.
Solve for x.
80 - 4x/x = 1,
80 = 5x,
x = 16 ans.
(42)
Surendar said:
2 months ago
Let assume cp = 100,
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
(42)
Vishal said:
2 years ago
25 % profit means 1/4.
20 cp = xsp.
sp/cp = 20/x.
So by formula;
1/4 = sp/cp - cp/cp.
5/4 = 20/x.
5x = 80.
x = 16.
20 cp = xsp.
sp/cp = 20/x.
So by formula;
1/4 = sp/cp - cp/cp.
5/4 = 20/x.
5x = 80.
x = 16.
(40)
Shahul Shaji said:
3 years ago
20 CP = x SP.
SP = (20/x) CP,
Profit = 25% = 125/100,
125/100 = 20/x,
x = 16.
SP = (20/x) CP,
Profit = 25% = 125/100,
125/100 = 20/x,
x = 16.
(38)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers