Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
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20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
354 comments Page 1 of 36.
Shiyaam said:
2 days ago
So simple;
Let ,Cp = 100.
25%proft = 25.
So, SP = 125,
100 × 20 = 125x,
X = 16.
Let ,Cp = 100.
25%proft = 25.
So, SP = 125,
100 × 20 = 125x,
X = 16.
(1)
Surendar said:
3 months ago
Let assume cp = 100,
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
(52)
Sree said:
3 months ago
Deriving formula:
S.P = [100 + gain% / 100 ] x C.P.
S.P is x.
C.P is 20x, so one CP is x/20,
x = 125/100 x (x/20),
x = 125x/2000,
2000x = 125x,
= 16.
S.P = [100 + gain% / 100 ] x C.P.
S.P is x.
C.P is 20x, so one CP is x/20,
x = 125/100 x (x/20),
x = 125x/2000,
2000x = 125x,
= 16.
(6)
Kaustubh said:
5 months ago
Let's say C.P of one article be "k" and S.P of one article be "y".
So, C.P of 20 article is "20k" and S.P of x article is "xy'
According to the question we know,
C.P of 20 article = S.P of x article.
Therefore, 20k = xy ------------> (1)
Also for a profit of 25% we can write equation as,
=> S.P of one article - C.P of one article / C.P of one article X 100 = 25
=> y - k / k = 1/4
=> 4y = 5k ------------> (2)
From equation (1) and (2) we can say that,
=> 16y - xy = 0,
=> y(16-x) = 0,
=> x = 16 [ANS].
So, C.P of 20 article is "20k" and S.P of x article is "xy'
According to the question we know,
C.P of 20 article = S.P of x article.
Therefore, 20k = xy ------------> (1)
Also for a profit of 25% we can write equation as,
=> S.P of one article - C.P of one article / C.P of one article X 100 = 25
=> y - k / k = 1/4
=> 4y = 5k ------------> (2)
From equation (1) and (2) we can say that,
=> 16y - xy = 0,
=> y(16-x) = 0,
=> x = 16 [ANS].
(11)
Pankaj said:
5 months ago
cp = xsp.
20 = 125%x
20 = 5/4x
20 * 4/4 = x.
16 = x.
20 = 125%x
20 = 5/4x
20 * 4/4 = x.
16 = x.
(23)
Kalyani said:
5 months ago
Let us assume c.p of one article = rs.1.
c.p of x articles = x,
s.p of x articles = c.p of 20 articles = 20,
profit = s.p-c.p = 20-x.
profit% = 25%.
profit% = (profit/c.p )* 100.
25 = (20-x/x )*100.
25x = 2000-100x.
2000 = 125x.
x=16.
c.p of x articles = x,
s.p of x articles = c.p of 20 articles = 20,
profit = s.p-c.p = 20-x.
profit% = 25%.
profit% = (profit/c.p )* 100.
25 = (20-x/x )*100.
25x = 2000-100x.
2000 = 125x.
x=16.
(13)
Siva said:
5 months ago
Let the CP of 20 articles be 100.
If SP is 25% profit, then it would be 125.
If 20 articles are 100.
Then,
x article is 125.
Just simply multiply the values and equal it;
x * 125 = 20 * 100.
x = 16.
If SP is 25% profit, then it would be 125.
If 20 articles are 100.
Then,
x article is 125.
Just simply multiply the values and equal it;
x * 125 = 20 * 100.
x = 16.
(25)
Shubham jaiswal said:
6 months ago
Given:
20cp = x sp.
20cp = 125% cp * x (because profit is 25 %).
20cp = 5/4 cp * x.
20 x 4/5 = x.
16 = cp.
20cp = x sp.
20cp = 125% cp * x (because profit is 25 %).
20cp = 5/4 cp * x.
20 x 4/5 = x.
16 = cp.
(10)
Dharshini said:
8 months ago
cp = 100 - 20 = 80,
sp = 25/100 * 20 = 5,
80/5 = 16.
sp = 25/100 * 20 = 5,
80/5 = 16.
(25)
AJAY said:
11 months ago
Let c.p(20) = s.p(x) = 100.
c.p(1) = 100/20 = 5
s,p(1) = 100/x.
Formula,
Profit =((s.p-c.p)*100/c.p
25=((100/x)-5)*100/5
By solving this you will get x = 16.
c.p(1) = 100/20 = 5
s,p(1) = 100/x.
Formula,
Profit =((s.p-c.p)*100/c.p
25=((100/x)-5)*100/5
By solving this you will get x = 16.
(20)
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