Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 7 of 36.
Riya said:
1 decade ago
Let us assume C.P of 20 articles = Rs. 100.
Then S.P of x articles = Rs. 100.
S.P of 20 articles = Rs. 125 (as profit= 25%).
Therefore 1 article = 125/20.
x article = (125*x) /20.
Which is again equals to 100.
Hence (125*x) /20=100.
x=16.
Then S.P of x articles = Rs. 100.
S.P of 20 articles = Rs. 125 (as profit= 25%).
Therefore 1 article = 125/20.
x article = (125*x) /20.
Which is again equals to 100.
Hence (125*x) /20=100.
x=16.
Tannu said:
1 decade ago
@sanjeet.
You really solve this problem in simple manner and it easy to understand. Thanks.
You really solve this problem in simple manner and it easy to understand. Thanks.
Abhi said:
1 decade ago
Hii.... friends i have done this problem in this method.
Dont know whether correct or wrong.please justify me.
c.p*20=s.p*x
Gain=25%
x=?
we know s.p=(100+gain%)/100 *cp
c.p*20=125/100 *cp *x
we will cancel cp on both sides.
by solving we will get x=16.
Dont know whether correct or wrong.please justify me.
c.p*20=s.p*x
Gain=25%
x=?
we know s.p=(100+gain%)/100 *cp
c.p*20=125/100 *cp *x
we will cancel cp on both sides.
by solving we will get x=16.
Shine said:
1 decade ago
Since the CP & SP are equal,
Profit%= ( (no.of items left over) / (no.of items sold) ) *100.
Let no.of items left over left over be X.
(X) / (20-X) = 0.25
On solving, no.of items sold= (20-X) =16.
Profit%= ( (no.of items left over) / (no.of items sold) ) *100.
Let no.of items left over left over be X.
(X) / (20-X) = 0.25
On solving, no.of items sold= (20-X) =16.
Sameer said:
1 decade ago
@Sanjeet nice explanation.
JOHNNY said:
1 decade ago
How we came to an assumption that cost of cost of each article = "RS 1" and cost of X articles is rs "X"
Vinay sharma said:
1 decade ago
Let the cost price of one article=Rs 100
profit=25%
SP =100+25=125
NOW
CP of 20 article =SP of X article
20 * 100 = 125 * X
X =16
profit=25%
SP =100+25=125
NOW
CP of 20 article =SP of X article
20 * 100 = 125 * X
X =16
Meena said:
1 decade ago
20*c.p=y --->1
s.p*x=y --->2
Cost price of 20 articles is 100%
Then selling price of x articles is 125%
20*100=2000 --->1
125*x=2000 --->2
x=(2000/125)=16
.'. x=16
s.p*x=y --->2
Cost price of 20 articles is 100%
Then selling price of x articles is 125%
20*100=2000 --->1
125*x=2000 --->2
x=(2000/125)=16
.'. x=16
Mr k said:
1 decade ago
One simple rule in this type of question.
When there is profit 25% it taken as 1.25
So. Equ will be : 20/x=1.25.
X=20/1.25.
X=16.
When there is profit 25% it taken as 1.25
So. Equ will be : 20/x=1.25.
X=20/1.25.
X=16.
Ashima said:
1 decade ago
Let CP of 1 article be 100rs.
p = 25 (because P% = P/CP*100).
SP = 100 +25 = Rs 125 ( P=SP-CP).
No of articles : CP (unitary method)
1 article - Rs 100.
20 articles - Rs 2000.
No. of articles: SP (unitary method)
1 article - Rs 125
x articles - Rs 2000 (remember CP of 20 = SP of x articles)
x= 2000/125 = 16 articles.
p = 25 (because P% = P/CP*100).
SP = 100 +25 = Rs 125 ( P=SP-CP).
No of articles : CP (unitary method)
1 article - Rs 100.
20 articles - Rs 2000.
No. of articles: SP (unitary method)
1 article - Rs 125
x articles - Rs 2000 (remember CP of 20 = SP of x articles)
x= 2000/125 = 16 articles.
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