Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
15
16
18
25
Answer: Option
Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

20 - x x 100 = 25
x

2000 - 100x = 25x

125x = 2000

x = 16.

Video Explanation: https://youtu.be/sidqvjUoZxY

Discussion:
353 comments Page 36 of 36.

Kaustubh said:   4 months ago
Let's say C.P of one article be "k" and S.P of one article be "y".

So, C.P of 20 article is "20k" and S.P of x article is "xy'

According to the question we know,
C.P of 20 article = S.P of x article.
Therefore, 20k = xy ------------> (1)

Also for a profit of 25% we can write equation as,
=> S.P of one article - C.P of one article / C.P of one article X 100 = 25
=> y - k / k = 1/4
=> 4y = 5k ------------> (2)

From equation (1) and (2) we can say that,
=> 16y - xy = 0,
=> y(16-x) = 0,
=> x = 16 [ANS].
(10)

Sree said:   3 months ago
Deriving formula:

S.P = [100 + gain% / 100 ] x C.P.
S.P is x.
C.P is 20x, so one CP is x/20,
x = 125/100 x (x/20),
x = 125x/2000,
2000x = 125x,
= 16.
(6)

Surendar said:   2 months ago
Let assume cp = 100,
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
(42)


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